The program should calculate the sum of all the prime numbers greater or equal to the input number 123456789101112131415161718192021222324252627282930313233343536 #include <iostream> #include <conio.h> #include <windows.h> using namespace std; int prime(int n) { for(int i...
I am not sure whether I should ask here or programmers but I have been trying to work out why this program wont work and although I have found some bugs, it still returns "x is not a prime number", even when it is. #include<iostream>usingnamespacestd;boolprimetest(inta){inti;//Hal...
Edit & run on cpp.shOct 31, 2014 at 1:17am shadowCODE (680) Algo 12345678 -start -count = 0 -for(i = 2; to ever) -if(i is a prim number) -add count by 1 if(count == 10) break; -endOct 31, 2014 at 1:19am MatthewRock (481) First of all - please fix your format...
As you know, only those numbers can be prime which have as their last digit either 1, 3, 7, or 9; and to check if that number is prime or not, you have to divide that number by previously found prime numbers only. So first take a group of four numbers = {1,3,7,9}, test i...
#include <iostream> using namespace std; int main () { int rows,columns; cout<<"Enter number of rows"<<endl; cin>>rows; cout<<"Enter the number of columns"<<endl; cin>>columns; double **A=new double *[rows]; int primenums, n ; for (int i=2;i<=rows;++i ) primenums[i]...
using namespace std; bool IsPrime (int); int main(void) { cout<<"The program checks if the given number is prime!"<<endl; for(int i= 0; i<=44; i++, cout<<'_'); cout<<endl; do { cout<<"Do you wish to test next number y/n->"; ...
using namespace std; //using namespace system; int isPrime(long num) // Returns 1 (true) if its prime, or 0 (false) if not { if (num < 2) // 1 is not a prime number return 0; // if it is > 2 and an even number, then it definitely is not a prime ...
using namespace std; //module prototype bool isPrime (int number); int main() { int number; string keepGoing; bool trueOrFalse; cout << "We are going to see if the positive integer you enter is a prime number or not." << endl; ...
using namespace std; //Returns true if the given number is a Prime number bool isPrime(int n) { if (n == 1) return false; // as 1 is not a prime number for (int i = 2; i <= sqrt(n); i++) // Complexity O(SquareRoot(n)) ...
using namespace std; int i; //int sqrt; //int j; int x; int j; int limit; bool primeNumber(int ); int main() { // cout << "Limit: "; // cin >x; // if ((x % 2 == 0) & (x % x == 0)) // { // return true; // } // else // { // return false; //...