百度试题 结果1 题目What is the sum of the prime factors of ?( ). A. B. C. D. E. 相关知识点: 试题来源: 解析 C 的质因子之和为? 首先,我们必须找到..我们把这些因子加起来. 故选.反馈 收藏
( ) A. B. C. D. E. 相关知识点: 试题来源: 解析 D \number{1000027}=100^{3}+3^{3}=(100+3)(\number{10000}-300+9)=103\times 9709=103\times 7\times 1387=103\times 7\times 19\times 73.The answer is .反馈 收藏 ...
Prime Factors of a Number Let us first see what factors of given numbers are. What does factorisation mean? The factorisation means writing a number as the product of its factors means in terms of its factors. Take a number say a and find the numbers which divide a. Now, the numbers wh...
百度试题 结果1 题目1. These are numbers with more than two factors. B A. Prime numbers C. Factors B. Composite numbers D. Multiples 相关知识点: 试题来源: 解析 B 反馈 收藏
The least integer with a prime number of different prime factors is.( )A. 6 B. 8 C. 12 D. 15 相关知识点: 试题来源: 解析 A 本题题意为“具有不同质数因子的最小整数是多少?”, 由题意可得,最小整数要具有不同的质数, 因此质数越小越好,至少要有两个质数, 因此这两个质数为2,3, ...
How many different prime numbers are factors of 1 million( ). A. oneB. twoC. threeD. ten相关知识点: 试题来源: 解析 B 1 million =106=(2×5)6=26×56. The only primes are 2 and 5. 有多少具不同的质数是一百万的因数( ). A.1 B.2 C.3 D.10 一百万的因数中,质数有2,5, 故...
What is the sum of the two smallest prime factors of 250?( ). A: 2 B: 5 C: D: 10 E: 12 相关知识点: 试题来源: 解析 C250最小的两个质因子之和为?250的主要因数分解是2.5^3.最小的两个是2和5.所以2+5=7.故选C.The prime factonzation of 250 is 2.5^3. The smallest two a...
The meaning of PRIME is first in rank, authority, or significance : principal. How to use prime in a sentence.
Another Note on the Greatest Prime Factors of Fermat Numbers For every positive integer k > 1, let P(k) be the largest prime divisor of k. In this note, we show that if F m = 2 2 m + 1 is the m 'th Fermat numb... A Grytczuk,M Wójtowicz,F Luca - 《Southeast Asian Bulleti...
The prime factorization of 48 is 2 x 2 x 2 x 2 x 3, where 2 and 3 are the unique prime factors of 48. The unique prime factor can be found by continuously dividing the number by prime numbers starting from 2. If a prime number divides the number, it is a prime factor. Repeat ...