returnarray_merge($this->primefactor($num/$i),array($i)); } } returnarray($num); } 看答案 来源有。您需要研究“Prime因分解”算法。如果将PHP添加为搜索要求,则可以找到比上面的蛮力方法更好的实现代码。开始这里. 请注意,Python方法没有显示任何事物关于算法:主要包具有内置算法,并且您仅调用的代码。...
非质数返回 False'''foriinrange(2,int(sqrt(n))+1):ifn%i==0:returnFalsereturnTruenum=600851475143# 初始答案值result=0# 初始因子factor=2whilefactor<=num:ifall([isPrime(factor),num%factor==0]):result=factornum/=factor# print(num)factor+=1# 不能用 for , for ...
示例代码(Python) python def prime_factors(n): """返回n的质因数分解结果,格式为字典""" factors = {} # 检查n的2的幂次 while n % 2 == 0: if 2 in factors: factors[2] += 1 else: factors[2] = 1 n //= 2 # 检查奇数因子 factor = 3 while factor * factor <= n: while ...
The prime factors of 13195 are 5, 7, 13 and 29. What is the largest prime factor of the number 600851475143 ? 欧拉题里很多是关于求质数,求质数的方法很多,我推荐的是筛选法,效率高,也很好理解。百度一下就有详细说明。 defprimeslist(max): a= [True]*(max+1) # 创建一个list,下标的位置就代...
Syntex:getFactorFermatTheorem(semiPrimeNumber) Return Type:tuple Note: This is only for composite number who have only two prime factors except number itself e.g. 33 have two prime factors 3 and 11. Pollard Rho for Factorization Syntex:getFactorPollardRho(semiPrimeNumber) ...
(num, "is not a prime number") elif num > 1: # check for factors for i in range(2, num): if (num % i) == 0: # if factor is found, set flag to True flag = True # break out of loop break # check if flag is True if flag: print(num, "is not a prime number") ...
# Python program to check prime number# Function to check prime numberdefisPrime(n):returnall([(n%j)forjinrange(2,int(n/2)+1)])andn>1# Main codenum=59ifisPrime(num):print(num,"is a prime number")else:print(num,"is not a prime number")num=7ifisPrime(num):print(num,"is a ...
Greatest Common Factor of 3 Numbers Online Quiz WorksheetsIntroduction to Distributive Property Online Quiz WorksheetsUnderstanding the Distributive Property Online Quiz WorksheetsIntroduction to Factoring With Numbers Online Quiz WorksheetsFactoring a Sum or Difference of Whole Numbers Online Quiz ...
import math def isprime(n): isPrime = True # assume it's prime until you find a factor for x in range(2,1+int(math.sqrt(n))): # check from 2 til squareroot of n # (the 1 + is so the for loop includes the sqrt) if n % x == 0: isPrime = False return isPrime But a...
14 + data.oversample_factor=4 \ 15 + data.return_raw_chat=True \ 16 + actor_rollout_ref.model.path=Qwen/Qwen2.5-0.5B \ 17 + actor_rollout_ref.actor.optim.lr=5e-7 \ 18 + actor_rollout_ref.model.use_remove_padding=True \ 19 + actor_rollout_ref.actor.ppo_mini_batch_size...