1vector<int> inorderTraversal(TreeNode*root) {2vector<int>rVec;3stack<TreeNode *>st;4TreeNode *tree =root;5while(tree || !st.empty())6{7if(tree)8{9st.push(tree);10tree = tree->left;11}12else13{14tree =st.top();15rVec.push_back(tree->val);16st.pop();17tree = tree->...
Postorder与Inorder很相似,但是比Inorder复杂的地方是如何判断该节点的左右子树都已经访问过了,按照Inorder的写法左子树还是先被访问,没有问题,但是访问完左子树后不能直接访问当前节点,要判断当前节点的右子树是否已经被访问,如果没有访问则应该继续去访问右子树,最后再访问当前节点 1vector<int> postorderTraversal(T...
顾名思义,在深度优先的情况下,在访问下一个同级树之前,树向下(向深度)遍历,二叉树的PreOrder,InOrder和PostOrder遍历实际上是深度优先遍历。在广度优先上,树的整个宽度在移到下一个级别之前被遍历,因此它也被称为级别顺序遍历。还有其他遍历二叉树的算法,例如蒙特卡洛树搜索,它集中于分析最优的移动,但先序、后序...
printf("Inorder traversal:the elements in the tree are"); inorder(root); printf(" Preorder traversal:the elements in the tree are"); preorder(root); printf("Postorder traversal:the elements in the tree are"); postorder(root); return 0;}...
inorder_visit(node_a);//中序 Console.WriteLine(); postorder_visit(node_a);//后序 Console.WriteLine(); node node_1 =newnode("1"); node node_2 =newnode("2"); node node_3 =newnode("3"); node node_4 =newnode("4");
Binary Tree Postorder Traversal 二叉树的后序遍历 -python 题目 给定一个二叉树,返回它的 后序 遍历。 链接:https://leetcode.com/problems/binary-tree-postorder-traversal/ Given a binary tree, return the postorder traversal of its nodes’ values. Example: Input: [1,null,2,3] 1 ......
inorder: left-root-right postorder: left-right-root order指的是root的位置。 recursive算法比较简单,iterative算法比较难想,可是leetcode原题都说了: recursive method is trivial, could you do iteration? 144.Binary Tree Preorder Traversal /*iterative*/ ...
The program creates a binary tree for breadth-first traversal.But i'm trying to use Pre-Order, In-Order, Post-Order Traversal and actually i can't do that. The output of the program is not what i expected. I think i should change the preorder, inorder or postorder functions but i ...
例如，给出 前序遍历 preorder = [3,9,20,15,7] 中序遍历 inorder = [9,3,15,20,7] 返回...
144. Binary Tree Preorder Traversal 这个系列有preorder inorder postorder三题,考点都不是递归,而是迭代。迭代挺难想的,尤其是外面的while循环。这题的迭代写法我模仿inorder写出来了,一步步在纸上模拟入栈出栈就好了。 RECURSION: ITERATION: 看了下discussion,很多跟我写的都不一样,说明迭代写法确实比递归...