Given preorder and inorder traversal of a tree, construct the binary tree.解决思路首先确定根节点,然后确定左右子树的节点数目。依次递归即可。假设输入的序列均合法。程序1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 ...
root=TreeNode(preorder[0]) i=inorder.index(preorder[0]) root.left= self.buildTree(preorder[1:1+i], inorder[:i]) root.right= self.buildTree(preorder[i+1:], inorder[i+1:])returnroot 同样的方法做106. Construct Binary Tree from Inorder and Postorder Traversal,后序和中序,建二叉树...
while(inorder[inorderLeftTreeEnd] != preorder[preBeg]) ++inorderLeftTreeEnd; int leftTreeSize = inorderLeftTreeEnd - inBeg; int rightTreeSize = (inBeg + size) - inorderLeftTreeEnd - 1; curNode->left = buildTree(preorder, preBeg+1, inorder, inBeg, leftTreeSize); curNode->righ...
for(int i=0;i<inorder.length;i++) { map.put(inorder[i],i); } return helper(preorder,0,preorder.length-1,inorder,0,inorder.length-1, map); } private TreeNode helper(int[] preorder, int preL, int preR, int[] inorder, int inL, int inR, HashMap<Integer, Integer> map) {...
INORDER AND PREORDER TRAVERSAL and DISPLAY OF EXISTING BINARY TREE IN COMPUTER MEMORYP K KumaresanJournal of Harmonized Research
order B. Traversing the forest corresponding to the binary tree in root-last order C. Traversing the forest corresponding to the binary tree in breadth-first order D. None of the above 答案：A 分析：正确答案:A 解析:前序遍历一个二叉树等价于按从树的根部、右子树、右子树查找顺序查找树。
15、课程:树(下).13、练习—Construct Binary Tree from Preorder and Inorder Traversal 1 -- 9:07 App 15、课程:树(下).3、练习—Floor and Ceiling 11 -- 12:45 App 13、课程:哈希表(下).10、作业讲解 3 -- 6:45 App 10、课程:堆栈和队列(上).10、练习—Min stack(一) 2 -- 6:07...
* Definition for a binary tree node. * public class TreeNode { * int val; * TreeNode left; * TreeNode right; * TreeNode(int x) { val = x; } * } */publicclassSolution{publicTreeNodebuildTree(int[]preorder,int[]inorder){if(preorder==null||inorder==null||preorder.length!=inor...
Given preorder and inorder traversal of a tree, construct the binary tree. Note: You may assume that duplicates do not exist in the tree. 翻译:给定树的前序和中序遍历,构造二叉树。 注意: 树中不存在重复项。 思路:首先,你应该知道 前序遍历:根节点,左子树,右子树; ...
Construct Binary Tree from Preorder and Inorder Traversal 题目描述(中等难度) 根据二叉树的先序遍历和中序遍历还原二叉树。 解法一 递归 先序遍历的顺序是根节点,左子树,右子树。中序遍历的顺序是左子树,根节点,右子树。 所以我们只需要根据先序遍历得到根节点,然后在中序遍历中找到根节点的位置,它的左边就...