此题元素是0,1,故可以不用保留每一步的计算,题目有要求限制O(1)的space, 也是给出提示,用一个变量retsum值来记录,每一步的prefix sum值,每移动一步,元素是1的话,将retsum 减1, 即是下一个prefix sum 值。 Detected time complexity: O(N) [100%] defsolution(A):# write your code in Python 2.7...
26 changes: 26 additions & 0 deletions 26 docs/basic/code/prefix-sum/prefix-sum_5.cpp Original file line numberDiff line numberDiff line change @@ -0,0 +1,26 @@ #include <iostream> #include <vector> int main() { int n; std::cin >> n; std::vector<int> a(1 << n); for...
C. Least Prefix Sum 链接https://codeforces.com/problemset/problem/1779/C题目思路1-m的前缀和最小。那么显然知道[1,m-1]的前缀和更大,所以a[m]<0,同理a[m-1]+a[m]<0,...,a[2]+...+a[m]<0。采用大根堆优先队列管理其中的值,如果上面的任何一个大于零,弹出优先队列的top,减掉两倍的top,...
由\begin{aligned} C'&=(C-\{x,y\})\cup\{z\}\\ z.\textit{freq} &= x.\textit{freq}+ y.\textit{freq}\\ d_T(x)&=d_T(y)=d_{T'}(z)+1\\ B(T)&=\sum_{c\in C}c.\textit{freq}\cdot d_T(c) \\ B(T')&=\sum_{c\in C'}c.\textit{freq}\cdot d_{T'}(c) ...
Breadcrumbs mojo-prefix-sum / std_cumsum_benchmark.mojoTop File metadata and controls Code Blame 109 lines (99 loc) · 5.74 KB Raw from algorithm import cumsum from time import now from math import min from prefix_sum import scalar_prefix_sum, simd_prefix_sum from prefix_sum_benchmark imp...
(GPU), a texture offset for a current segment of a plurality of ordered segments of a dashed line, where the texture offset for the current segment of the plurality of ordered segments is based on an accumulation of lengths of segments that precede the current segment in the order, and ...
We present several fast algorithms for multiple addition and prefix sum on the Linear Array with a Reconfigurable Pipelined Bus System (LARPBS), a recently proposed architecture based on optical buses. Our algorithm for adding N integers runs on an N log M-processor LARPBS in O(log* N) time...
CUDA C Code for the Work-Efficient Sum Scan of Algorithms 3 and 4.The highlighted blocks are discussed in Section 39.2.3.Copy __global__ void prescan(float *g_odata, float *g_idata, int n) { extern __shared__ float temp[]; // allocated on invocation int thid = threadIdx.x; int...
Let the longest codeword have length ; then a full or complete binary tree will have 2lmax leaves. As can be seen from the example in Figure 9.A–2, each codeword with length li is seen to prune off a total of leaves. Taking the sum of these removed leaves, we have . Canceling ...
Example 39-2. CUDA C Code for the Work-Efficient Sum Scan of Algorithms 3 and 4. The highlighted blocks are discussed in Section 39.2.3. __global__ void prescan(float *g_odata, float *g_idata, int n) { extern __shared__ float temp[]; ...