publicbooleanisPowerOfTwo3(intn){if(n<1) {returnfalse; }Stringstr=Integer.toBinaryString(n);returnstr.indexOf("1") == str.lastIndexOf("1"); } 05 第四种解法 特殊情况:当n小于1的时候,直接返回false。 正常情况:借助包装类Integer,使用其bitC
public boolean isPowerOfTwo(int n) { int power = 1; while (power <= n) { if (power == n) { return true; } power = power << 1; // if (power == Integer.MIN_VALUE) if (power == -2147483648) { break; } } return false; } 当然有一点需要注意,需要了解一些补码的知识,参考 ...
LeetCode Top Interview Questions 231. Power of Two (Java版; Easy) 题目描述 Given an integer, write a function to determine if it is a power of two. Example 1: Input: 1 Output: true Explanation: 20 = 1 Example 2: Input: 16 Output: true Explanation: 24 = 16 Example 3: Input: 218...
java工具类 isPowerOfTwo,代码顺序 查看代码 package org.example; import com.google.common.math.IntMath; import com.google.common.math.LongMath; import java.math.RoundingMode; import java.util.stream.Stream; public class GuavaTester { public static void main(String[] args) { short short1 = 0b...
leetcode231. Power of Two 题目要求 Given an integer, write a function to determine if it is a power of two. 判断一个整数是否是2的幂。 思路和代码 当我们从二进制的角度来看,这个题目就非常简单了。其实题目的要求等价于该整数对应的二进制数中,一共有几个1。该题目的难点在于考虑边界情况,比如-2...
org/Java-guava-ispoweroftwo-method-int math-class/番石榴的 IntMath 类的是PowerOfTwo() 方法,用于检查一个数是否是二的幂。它接受要检查的数字作为参数,并根据该数字是否为 2 的幂返回布尔值 true 或 false。语法:public static boolean isPowerOfTwo(int x) ...
Power of Two Given an integer, write a function to determine if it is a power of two. 整除法 复杂度 时间O(1) 空间 O(1) 思路 最简单的解法,不断将原数除以2,一旦无法整除,余数不为0,则说明不是2的幂,如果整除到1,说明是2的幂。
java源码 public final class Math { private Math() {} public static double scalb(double d, int scaleFactor) { // magnitude of a power of two so large that scaling a finite // nonzero value by it would be guaranteed to over or
Java program to check if number is power of two: In this tutorial, we will see how to check if number is power of two. There are many approaches to check if number is power of two or not. Approach 1: It is very easy and straight forward approach. Run a while loop which checks fo...
bigintermath ceilingPowerOfTwo()函数|番石榴| Java 原文:https://www . geesforgeks . org/bigintermath-ceilingpoweroftwo-function-guava-Java/ 番石榴的大整数类的ceilingPowerOfTwo(big integer x)方法返回大于或等于 x 的 2 的 最小幂 ,这相 开发文档