* three ways to solution this problem */#include<stdio.h>#include<stdbool.h>#include<math.h>#definesolution 3boolisPowerOfThree(intn){#ifsolution==1//循环迭代while(n) {if(n==1)returntrue;if(n%3!=0)returnfalse; n /=3;if(n ==1)returntrue; }returnfalse;#elifsolution==2//32位...
In order to solve for 2 to the power of 3, we must first understand the structure. The number 2 is called the base, and the number 3 is called the exponent. In short, the base must be multiplied by itself the number of times as the exponent. Let’s look at this problem in more...
returnn%3==0andself.isPowerOfThree(n/3) Python: 1 2 3 4 5 6 7 classSolution(object): defisPowerOfThree(self, n): """ :type n: int :rtype: bool """ returnn >0and3**round(math.log(n,3))==n Python: 1 2 3 classSolution(object): defisPowerOfThree(self, n): returnn ...
题目简单,判断一个数字是否为3个次方。要求不能用for循环。 给出的条件是n是int类型,不是long类型。二. 代码 class Solution { public boolean isPowerOfThree(int n) { // 3^19 < Integer.Max, 3^20 > Integer.Max return ( n>0 && Math.pow(3,19)%n==0); } }发布...
Math can be found everywhere in daily life 生活中,数学无处不在 Traffic solutions Have you ever wondered how the timing of traffic lights is decided to avoid traffic jams (拥堵)? Traffic engineers use special math models ca...
Given an integer n, returntrue if it is a power of two. Otherwise, return false. An integer n is a power of two, if there exists an integer x such that n == 2x. class Solution { public boolean isPowerOfTwo(int n) { return n>0 && (n&n-1)==0; ...
The ultimate Aim of ASIC verification is to obtain the highest possible level of confidence in the correctness of a design, attempt to find design errors and show that the design implements the specification. Complexity of ASIC is growing exponentially a
Given an integer, write a function to determine if it is a power of three. Follow up: Could you do it without using any loop / recursion?大意:给出一个整数,写一个函数来判断它是否是3的次方数。 进阶: 你能不能不用循环和递归来做?
The syntax needed to call a static .NET method is brackets around the class followed by two colons and then the name of the method: [System.Math]::Pow(2,3). If you’re running this in the ISE, press F5 (or click the Run button) to ...
建议和这一道题leetcode 342. Power of Four 4的幂指数 一起学习。 代码如下: /* * 使用3的幂数的相关解法,使用log很不错,第二个也很不错 * */ public class Solution { public boolean isPowerOfThreeByLog(int n) { double res=Math.log10(n) / Math.log10(3); ...