postgresql count distinct window-functions cumulative-sum 1个回答0投票 我认为针对不同聚合查询的自连接将会执行: select *, sum(distinct_product_count) over(partition by territory_id order by quarter_num) as cum_filtered_product_count from some_table left join ( select territory_id, quarter_num...
(1)sum函数,统计总和 按照月份,统计每个地区的总收入 (2)rank() over开窗函数 按照月份、地区,打工收入排序 (3)关于Row_number() Rank() Dense_rank()规则 解析:通用语法 区别:Row_number() over(partition by A,B order by C,d) 本条记录所有列都相同的时候,编号列如下 (1 2 3)没有并列第二 rank...
5 SQL query for accumulated sum using window function in postgresql 1 How to adapt this query to use window functions 2 Cumulative sum over a table 2 Stock calculation in Postgres 0 SQL - cumulative sum in postgres 4 running sum with window function 1 Cumulative sum of multiple wind...
SELECT department, SUM(sales) OVER (PARTITION BY department) AS total_sales FROM sales_table; 计算每个月的销售额及累计销售额: 代码语言:txt 复制 SELECT month, sales, SUM(sales) OVER (ORDER BY month) AS cumulative_sales FROM sales_table; 计算每个部门的销售额排名: 代码语言:txt 复制 ...
If you want a cumulative sum: SELECTp.*,SUM(monthly_return)OVER(PARTITIONBYportfolio_idORDERBYdate)asrunning_monthly_returnFROM(SELECTdate, portfolio_id, (value_cents*0.01-cash_flow_cents*0.01)/(lag(value_cents*0.01,1)over(ORDERBYportfolio_id,date))-1ASmonthly_returnFROMportfolio_balancesWHERE...
SELECT column1, column2, ..., SUM(column3) OVER (ORDER BY column1 ROWS BETWEEN UNBOUNDED PRECEDING AND CURRENT ROW) AS cumulative_sum FROM table 在上述查询中,column1、column2等是表中的列名,column3是要计算的列。SUM函数用于计算累积和,而窗口函数的PARTITION BY子句用于指定分区,ORDER BY子句用于...
-- 员工ID department, -- 部门 salary, -- 薪水 SUM(salary) OVER (PARTITION BY department ORDER BY salary DESC) as cumulative_salary, -- 计算当前员工及薪水更高的员工的累计薪水 RANK() OVER (PARTITION BY department ORDER BY salary DESC) as salary_rank -- 计算员工在本部门内的薪水排名 FROM...
SUM(amount) OVER (PARTITION BY customer_id ORDER BY payment_date) as cumulative_amount FROM payment ORDER BY payment_date; 现在我们打开 dbForge Studio for PostgreSQL 并运行 ChatGPT-4 为我们生成的查询。 让我们向 Google Bard 问同样的问题。
SUM(amount) OVER (PARTITION BY customer_id ORDER BY payment_date) as cumulative_amount FROM payment ORDER BY payment_date; 现在我们打开 dbForge Studio for PostgreSQL 并运行 ChatGPT-4 为我们生成的查询。 让我们向 Google Bard 问同样的问题。
-- 薪水 SUM(salary) OVER (PARTITION BY department ORDER BY salary DESC) as cumulative_salary...