JAVA中Postfix递减中的StackOverFlow 这工作得很好,因为我们在递归调用中使用了前缀递减运算符!前缀递减: publicstaticvoidmain(String[] args){ doubt1(5); }staticvoiddoubt(intnum){if(num==0)return; System.out.println(num); doubt(--num); } 后缀递减: staticvoiddoubt1(intnum){if(num==0)return;...
(Val_2/Val_1);// Perform divide operationbreak;case'*':EqStack.push(Val_2*Val_1);// Perform multiply operationbreak;}}}returnEqStack.pop();}publicstaticvoidmain(String[]args){String EXP="82*9+";// The expression stringSystem.out.println("Postfix evaluation result: "+EvaluatePostfix(...
public class PostfixEvaluation { public static void main(String[] args) { String postfix = "23+79*-"; Stack stack = new Stack(); for (int i = 0; i < postfix.length(); i++) { if (postfix.charAt(i) == '+') { int v1 = stack.pop(); int v2 = stack.pop(); stack.push...
Computer evaluation of postfix Going left to right, –If you see a number, put it on the stack –If you see an operator, pop two numbers from the stack, do the operation, and put the result back on the stack (The top number on the stack is the operand on the right) The result i...