请在下面的文本框内输入文字,然后点击开始翻译按钮进行翻译,如果您看不到结果,请重新翻译!post order traversal选择语言:从 到 翻译结果1翻译结果2 翻译结果3翻译结果4翻译结果5 翻译结果1复制译文编辑译文朗读译文返回顶部 后序遍历 翻译结果2复制译文编辑译文朗读译文返回顶部 邮汇单traversal 翻译结果3复制译文编辑...
Doing a Post-order Traversal on a Binary Tree can be visualized like this: Result: Post-order Traversal works by recursively doing a Post-order Traversal of the left subtree and the right subtree, followed by a visit to the root node. It is used for deleting a tree, post-fix notation ...
递归post-order 分治Divide&Conquer dfs来upwards累积 classSolution{publicintminDepth(TreeNoderoot){if(root==null)return0;intleft=minDepth(root.left);intright=minDepth(root.right);return(left==0||right==0)?left+right+1:Math.min(left,right)+1;}} Binary Tree Postorder Traversal Recursive classS...
An alternative solution is to use two stacks. Try to work it out on a piece of paper. I think it is quite magical and beautiful. You will think that it works magically, but in fact it is doing a reversed pre-order traversal. That is, the order of traversal is a node, then its r...
Detailed explanation:Morris Inorder Tree Traversal This algorithm can only be used to solve pre/in order. class Solution{public:voidrecoverTree(TreeNode*root){TreeNode*current=root;TreeNode*first=NULL;TreeNode*second=NULL;TreeNode*pre=NULL;while(current){if(!current->left){if(pre&&pre->val>...
求翻译:post order traversal是什么意思?待解决 悬赏分:1 - 离问题结束还有 post order traversal问题补充:匿名 2013-05-23 12:21:38 后序遍历 匿名 2013-05-23 12:23:18 正在翻译,请等待... 匿名 2013-05-23 12:24:58 岗位顺序遍历 匿名 2013-05-23 12:26:38 开机自检顺序遍历 匿名 ...
For each test case, first printf in a line Yes if the tree is unique, or No if not. Then print in the next line the inorder traversal sequence of the corresponding binary tree. If the solution is not unique, any answer would do. It is guaranteed that at least one solution exists. ...
在下文中一共展示了AVL::postOrderTraversal方法的1个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的C++代码示例。 示例1: main ▲点赞 7▼ intmain(){intSIZE=20;vector<int> v(SIZE); ...
export function postorderTraversal(root: TreeNode): number[] { // write code here if(root === null) return []; return [._牛客网_牛客在手,offer不愁
// traversing binary tree using post-order traversal using recursion System.out.println("printing nodes of a binary tree on post order in Java"); bt.postOrder(); } } classBinaryTree { staticclassTreeNode { String data; TreeNode left, right; ...