This article mainly introduces how to find the position of an element in a list using Python, which is of great reference value and hopefully helpful to everyone. How to Find the Position of an Element in a List Problem Description Given a sequence containing n integers, determine the position...
Example 1: Get the Position of an Element Using the “index()” Method from the Python List The “index()” method integrated into Python provides a basic and straightforward technique to discover the location of an element in a list. If the element exists, it delivers the index of its i...
题目地址:https://leetcode.com/problems/find-first-and-last-position-of-element-in-sorted-array/description/ 题目描述 Given an array of integers nums sorted in ascending order, find the starting and ending position of a given target value. Your ...
classSolution:defsearchRange(self,nums,target):""":type nums:List[int]:type target:int:rtype:List[int]""" length=len(nums)iflength==0:return[-1,-1]ifnums[0]<=target and nums[-1]>=target:left,right=0,length-1whileleft<=right:mid=(left+right)// 2ifnums[mid]==target:right=left...
34. Find First and Last Position of Element in Sorted Array Given an array of integers nums sorted in ascending order, find the starting and ending position of a given target value. Your algorithm's runtime complexity must be in the order of O(log n). ...
或者可以直接使用python自带的bisect库里的函数实现: classSolution:defsearchRange2(self,nums:List[int],target:int)->List[int]:ifnotnums:return[-1,-1]# bisect_left可以获得target插入nums中的位置,若有相同元素则返回最左边的位置# bisect_right则是返回最右边的位置# 例 nums = [1,2,2,3],...
解决思路:二分查找直到找到第一个目标值,再对目标值左右进行二分查找 Python代码: classSolution(object):defsearchRange(self, nums, target):""":type nums: List[int] :type target: int :rtype: List[int]"""l=0 r= len(nums)-1whilel <=r : ...
Python Code: # Define a function called 'shift_first_last' that shifts the first element to the last position and the last element to the first position of a list.defshift_first_last(lst):# Remove the first element and store it in 'x'.x=lst.pop(0)# Remove the last element and sto...
python def insert_element(lst, index, element): # 检查索引有效性 if index < 0 or index > len(lst): raise IndexError("Index out of range") # 执行插入操作 lst.insert(index, element) # 验证插入结果(打印列表) print(f"After insertion, the list is: {lst}") # 示例用法 my_list...
class Solution: def searchRange(self, nums: List[int], target: int) -> List[int]: low = 0 high = len(nums)-1 mid = 0 if high<0: return [-1, -1] while low<=high: mid = (low+high)//2 if nums[mid]==target: break ...