我明白你的意思,其实四分频的代码写成always@(posedge clk_in or negedge rst) begin if(~rst) clk_out4_r lt;= 0; else if(clk_out2_r) clk_out4_r lt;= ~clk_out4_r; end就会是_牛客网_牛客在手,offer不愁
always@(posedge clk_in or negedge rst)begin if(!rst) cnt <= 3'b000; else cnt <= cnt-1; end (写成这样更好理解) 03-31 21:12 中山大学 算法工程师 第一次创业,我要被气吐血了 今天,项目组的一个成员走了,开发的任务分担在我们身上,又重了几分,我真的好生气,他在走之前说了句我觉得我适...
always@( posedge clk or negedge rst) begin if (!rst) int_reg <= 0; else int_reg <= in; end assign out = ~ int_reg & in; A.检测in的上升沿 B.检测in的下降沿 C.检测in的低电平 D.检测in的高电平 你可能感兴趣的试题 问答题 ...
always@(posedge CLK) and elsewhere I find: assign CLK_n = ~CLK; always@(negedge CLK_n) It would seem to me that the later is an oddly complicated way to say the same as the former. I assume I'm missing something here and there's an excellent reason for doing it this ...
always @ (posedge clk or negedge alarm_in) begin if(alarm_in == 1'b0) alarm_outr <= 1'b0; else if(cnt_s == set_s && cnt_m == set_m && cnt_h == set_h) alarm_outr <= 1'b1; end Generally, you should consider that an edge sensitive always block stands for a DFF, ...
B、检测in的下降沿 C、检测in的高电平 D、检测in的低电平查看答案更多“如果输入信号为in,输出信号为out,则以下程序的功能是?() reg int_reg; always@(posedge clk or negedge rst) begin if (!rst) int…”相关的问题 第1题 以下哪些是加强型回路 A、倒一杯水 B、路径依赖 C、增长上限 D、网络...
always@(posedge CLK) and elsewhere I find: assign CLK_n = ~CLK; always@(negedge CLK_n) It would seem to me that the later is an oddly complicated way to say the same as the former. I assume I'm missing something here and there's an excellent reason for doing it this ...
always@(posedge CLK) and elsewhere I find: assign CLK_n = ~CLK; always@(negedge CLK_n) It would seem to me that the later is an oddly complicated way to say the same as the former. I assume I'm missing something here and there's an excellent reason for doing it this way....
always@(posedge CLK) and elsewhere I find: assign CLK_n = ~CLK; always@(negedge CLK_n) It would seem to me that the later is an oddly complicated way to say the same as the former. I assume I'm missing something here and there's an excellent reason for doing it this ...
always@(posedge CLK) and elsewhere I find: assign CLK_n = ~CLK; always@(negedge CLK_n) It would seem to me that the later is an oddly complicated way to say the same as the former. I assume I'm missing something here and there's an excellent reason for doing it this way....