input clk, reset, in, output out ); reg trig1 = 0, trig2 = 0; assign out = trig1 ^ trig2; always @(posedge clk, posedge reset) begin if (reset) trig1 <= 0; trig1 <= in^trig2; end always @(negedge clk, posedge reset) begin if (reset) trig2 <= 0; trig...
不能那么写。send_start比较长打一拍就行了 reg send_start_d;always@(posedge CLK_SP)send_start_d <= send_start;这样上升沿可以写成 if(send_start_d == 1'd0 && send_start == 1'd1)就是上一拍还是0这一拍是1我们就认为他是上升沿了 ...
下面程序中信号in、a、b和c的初值分别为0、1、2和3,那么经过1个时钟周期后,c的值是( )。 always @(posedge clk) begin a b c end A. 0 B. 1
已知状态转移图如下:请将在下划线处填写正确的代码: module reduce (clk, reset, in, out); input clk, reset, in; output out; parameter S0 = 2’b00; parameter S1 = 2’b01; parameter S2 = 2’b10; reg out; reg [1:0] state; reg [1:0] next_state; always @(posedge clk) if (reset...
always@(posedge clk_in or negedge rst)begin if(!rst) cnt lt;= 3#39;b000; else cnt lt;= cnt-1; _牛客网_牛客在手,offer不愁
1 Wondering about the behavior of event control statements in an always block: always @(posedge clk) begin: TEST ... @(wait_for_signal_from_subsystem); ... @(wait_for_another_signal_from_subsystem); ... end Will the process be "stuck" until the event signals come in, or will ...
分享31 svc吧 天天看_电视1 用verilog HDL设计一个五三分频器,输入时钟占空比为1:1module divider( clk_in, rst, mode, clk_out ); input clk_in; input rst; input mode; output clk_out; reg [3:0] cnt1; reg [3:0] cnt2; wire level_gen; reg level_chg; wire [1:0] mode; reg clk_...
module SHIF4(DIN,CLK,RST,DOUT); input CLK,DIN,RST; output DOUT; reg [3:0] SHFT; always@(posedge CLK or posedge RST) if (RST) SHFT else begin SHFT>1);SHFT[3] assign DOUT=SHFT[0]; endmodule 该程序实现的功能是: A. 右移移位寄存器
a. The ‘always @(posedge clk)’ block violates the Verilog synthesis coding guidelines we discussed in class. What are these violoations? Show how this ‘always’ block should be written. The always block used blocking assignments (‘=’) when it should have used non-blocking a... 文档...
always @ (posedge clk or negedge alarm_in) begin if(alarm_in == 1'b0) alarm_outr <= 1'b0; else if(cnt_s == set_s && cnt_m == set_m && cnt_h == set_h) alarm_outr <= 1'b1; end Generally, you should consider that an edge sensitive always block stands for a DFF, ...