print "pop the last item Error:",e #调用creatList函数创建表 listOne=creatList() #输出创建表信息 print "The init list :",listOne #调用popTheFirst函数删除并返回第一个元素 theFirst=popTheFirst(listOne) #输出当前表的第一个元素 print "The first item of list:",theFirst #调用popTheFirst函数...
# 栈stack = [1, 2, 3]top_element = stack.pop()print(top_element)print(stack)# 队列queue = ['Alice', 'Bob', 'Charlie']first_person = queue.pop(0)print(first_person)print(queue)输出结果:3[1, 2]Alice['Bob', 'Charlie']替换元素 pop方法还可以用来替换列表中的指定位置的元素。通过先...
Inserting an item to the deque by specifiying the index deque(['guava', 'pear', 'banana', 'strawberry', 'apple', 'mango', 'orange', 'papaya', 'grapes', 'watermelon']) Popping out last item from the right watermelon Popping out first item from the left guava Removing an item from...
请求到数据前端增加自定义字段控制列表收起展开 v-for="(item, index) in listData"表格循环列表, @click="toogleExpand(index)"点击事件 v-show="item.active"收起展开 请求到数据前端自定义字段 getList() { Axios.post( 'admin/vue/...问答精选Android...
def add(self,item): temp = Node(item) #create a new node with the `item` value temp.next = self.head #putting this new node as the first (leftmost) item in a list is a two-step process. First step is to point the new node to the old first (lefmost) value self.he...
Python删除列表元素问题 列表中的项目是元组,只需对其进行迭代即可获得这些元组中的项目: print([item for tup in output for item in tup]) 如果元组类似于[("apple","something-else"), ("orange",), ("banana",)],则此解决方案将起作用 由于在您的情况下只有一项,您还可以执行以下操作: print([tup[...
Challenge: reverse a list using while .pop() insert() pop() the first item in the list and add to the beginning of a new string that will be reversed some_numbers =[1,2,3,4,5,6,7,8,9,11,22,33,44,55,66,77] Here's the code I have written: some_numbers =[1,2,3...
pop(2) print(city) print("List Elements: ",cities) Output Mumbai List Elements: ['London', 'Paris', 'New York'] New York List Elements: ['London', 'Paris'] In the above example, cities.pop(0) returns the first element and removes it. cities.pop(2) returns and removes element ...
list.pop(index) Example fruits = ["apple", "banana", "cherry"] cherry = fruits.pop(2) print(cherry) # Output: "cherry" print(fruits) # Output: ["apple", "banana"] remove() Theremove()method removes the first occurrence of a specified item in the list. If the item is not found...
In the above example, the pop() method is called twice with an index of 0, which removes and returns the first item in the letters list, and then the second item. The two removed items are returned as a tuple, which is assigned to the first_two_letters variable....