#include<iostream>#include<cstring>#include<cstdio>usingnamespacestd;intprime[20005];voidinit(){inti,j; memset(prime,0,sizeofprime); prime[1] =1;for(i=2;i<=20000;i++){if(prime[i]==0){for(j=i;j<=20000;j+=i){ prime[j]=i; } } } }intmain(){intn,maxn,t,ans; init()...
poj3048--Max Factor(最大素数因子) 通过素数筛选,加输入时判断,效率不是很高 View Code
//By SiriusRen#include <cstdio>#define N 200000using namespace std;intn,mindiv[200050],prime[100000],top=0,xx,rec;intmain(){for(inti=2;i<=N;i++) {if(!mindiv[i])prime[++top]=mindiv[i]=i;for(intj=1;j<=top&′[j]*i<=N;j++) { mindiv[prime[j]*i]=prime[j];if(!(...
POJ - 3048 (最大素因数) To improve the organization of his farm, Farmer John labels each of his N (1 <= N <= 5,000) cows with a distinct serial number in the range 1..20,000. Unfortunately, he is unaware that the cows interpret some serial numbers as better than others. In par...
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POJ 3048 Max Factor (筛素数) Description To improve the organization of his farm, Farmer John labels each of his N (1 <= N <= 5,000) cows with a distinct serial number in the range 1..20,000. Unfortunately, he is unaware that the cows interpret some serial numbers as better than ...
poj 3048 Max Factor(素数筛) 这题就是先写个素数筛,存到prime里,之后遍历就好,取余,看是否等于0,如果等于0就更新,感觉自己说的不明白,引用下别人的话吧: 素数打表,找出20000之前的所有素数,存入prime数组,对于每个输入的数a,从prime数组最后一个数往前判断,如果a % prime[当前序号]== 0,那么将该素数就是...
POJ 3048 线性筛法求素数 一个坑: 有组数据如下: 1 1 坑很深…… //By SiriusRen #include <cstdio> #define N 200000 using namespace std; int n,mindiv[200050],prime[100000],top=0,xx,rec; int main(){ for(int i=2;i<=N;i++)...
poj3048 Max Factor 题意:求质因子最大的数 思路:线性筛打表即可 View Code
POJ3048 HDU2710 Max Factor USACO 2005 October Bronze 筛选法不仅能够用来计算最小的若干素数,也可以用来求整数的最大公因子。 问题链接:POJ3048 HDU2710 Max Factor。基础训练级的题,用C语言编写。 问题简述:测试数据有多组,每组先输入n,然后输入n个正整数,输出n个正整数中,素因子最大的那个数。