“expression must have pointer-to-object type” 错误详解 1. 错误信息含义 错误信息“expression must have pointer-to-object type”通常表明在代码中使用了非指针类型的表达式,但在该上下文中编译器期望一个指向对象的指针类型。这通常发生在使用了指针操作(如解引用*、下标[]等)或尝试将非指针类型的变量传递给...
因为子文件中引用主程序定义的结构体出错。解决:将子程序文件中 子函数移至主文件。结构体也是一种数据类型，只不过在这种数据类型中又包含了几个基本的数据类型。构体变量在内存中的存放和基本数据类型变量在内存中的存放是不同的，基本数据类型的存放系统是会给分配一块连续的空间用来存放，而结构体...
A = X[rows][1]; for ( count=0;count<Q;count++) { value_buf[count] = A[count]; // delay(); } #143 expression must have pointer-to-object type
1.不能更精确地指明其转型的意图。 如将一个pointer-to-base-class-object转型为一个pointer-to-derived-class-object(改变一个对象的类型)和将一个pointer-to-const-object转型为一个pointer-to-non-const-object(改变对象的常量性),在旧式C语法中并不区分。 2.难以辨识。 旧式C转型方式的语法为(type)expressi...
expression must have pointer-to-object type是编译器给出的错误信息,意思是表达 c语言为什么报错expression must have pointer-to-object type(代码很短) 因为子文件中引用主程序定义的结构体出错。解决:将子程序文件中 子函数移至主文件。结构体也是一种数据类型,只 c 基础框架代码和c 基础框架代码的响应式原理...
问出现"void* is not a pointer-to-object type“错误，但代码在使用XCode时可以完美执行ENStruts has...
expression must have pointer-to-object or handle-to-C++/CLI-array type Problem Expression:(L"Buffer is too small" &&0) error from strcpy_s() function Extract String from EXE Extract strings from process memory f:\dd\vctools\vc7libs\ship\atlmfc\src\mfc\doctempl.cpp FAQ: 2.17 How do ...
The last 0 is where the pointer to the array in object is lost. Also the pointer to the object did not follow the address change. With -Dsplit=1, it will return from the subroutine where the object is constructed, then construct the object reference, and...
cout<<*ptr; //Error Message: 'void*' is not a pointer-to-object type getch(); } Please help, why this error occuring? Dec 14, 2012 at 1:44pm Zhuge(4664) You tell the compiler to dereference ptr, but since ptr is void* it has no idea what the memory at ptr is meant to look...
A conversion shall not be performed between a pointer to object type and a pointer to a different object type.