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We investigate the ultra-violet behavior of non-compact lattice QED with ligth staggered fermions. The main question is whether QED is a non-trivial theory... M G?Ckeler,R Horsley,P Rakow,... - 《Nuclear Physics B》 被引量: 95发表: 1992年 Power corrections and resummation of radiative...
It has more or less just become the standard, and very few question why one has a gravity constant G that is multiplied by M. For example In her recent book, “Existential Physics” [55], Hossenfelder makes the claim that “Newton’s constant (G) quantifies the strength of gravity....
Im looking for an upgrade later this year (still waiting for some refresh from razer to the book and the surface laptop 4), but as of right now, between this one and Asus ZenBook S 13.. Is it possible for u to post a side by side comparison? I have the measurements, and know thi...
(which, however, is possible if it is displayed on an, e.g., liquid-crystal spatial light modulator). This limitation is slightly mitigated by the fact that the TC of the OV in them-th diffraction order ismtimes higher than the one reproduced in the first diffraction order. It was ...
OpenAI于2023年3月份启动了Plugins插件计划,并开放了候补名单。这一计划旨在为用户提供更多的插件功能,包括自然语言处理、图像识别、知识图谱等方面的功能,从而为用户提供更强大的人工智能应用。 在此计划的推动下,OpenAI于5月12日逐步开放了ChatGPT插件功能,并且ChatGPT现在也支持联网访问。这意味着,用户可以利用插件功...
more straightforward, but poses the question of the most suitable metric for measuring the suitability of an answer. An interesting topic of research would be to study what are the characteristics of complex (numerical) research problems, as in quantum physics research, that indicate the usefulness...
截至2023年5月16日,目前可以添加70多种插件,看文末附表。插件将 ChatGPT 连接到外部应用程序。如果启用了一个插件,ChatGPT 可能会将你的部分对话以及你所在的国家或州发送到该插件,以增强你的对话。ChatGPT会根据您启用的插件自动选择在对话中何时使用插件。插件由不受 OpenAI 控制的第三方应用程序开发,在安装之前...
CoActuem per la Salut Mental chatbot. The mobile of one participant has just received a micro-story from a person with lived experience in mental health. The chatbot is asking a concrete question, and the participant needs to select one of the possible answers ...
A question of crucial importance is whether the Numerov method displays a good convergence rate. For this purpose, following Refs. [22,23,24,25], one can evaluate from the values in Table 1 the quantity $$\begin{aligned} N_{k}=\log _{2}\left( {|A_{k-2}-A_{k-1}|\over |A_...