function removeTrailingZeros($number) { if (strpos($number, '.') !== false) { $number = rtrim($number, '0'); // 如果末尾还有.的话也去掉 if (substr($number, -1) == '.') { $number = rtrim($number, '.'); } } return $number; } $number = "123.45000"; echo removeTrailing...
November 28, 2018 Last visited 5 hours ago Days Won 17 Everything posted by gw1500se 1 2 3 4 5 6 Next Page 1 of 34 Prevent php from removing trailing zeros gw1500sereplied toadmien's topic inPHP Coding Help Use sprintf. You can convert the number to whatever format you want to enf...
SakiTakamachi self-assigned this Dec 6, 2024 SakiTakamachi mentioned this issue Dec 6, 2024 et/bcmath - Fixed GH-17061: Now Number::round() does not remove trailing zeros #17063 Draft Sign up for free to join this conversation on GitHub. Already have an account? Sign in to comment ...
//eg $sciNotation = 2.3649E-8 $number = number_format($sciNotation, 10); //Use $dec_point large enough echo rtrim($number, '0'); //Remove trailing zeros 1. 2. 3.
Fixed bug GH-17061 (Now Number::round() does not remove trailing zeros). Fixed bug GH-17064 (Correctly round rounding mode with zero edge case). Fixed bug GH-17275 (Fixed the calculation logic of dividend scale). Core: Fixed bug OSS-Fuzz #382922236 (Duplicate dynamic properties in hooked...
本文转自:https://stackoverflow.com/questions/4576927/convert-a-string-containing-a-number-in-scientific-notation-to-a-double-in-php //eg$sciNotation= 2.3649E-8$number= number_format($sciNotation, 10); //Use$dec_pointlarge enoughechortrim($number,'0'); //Remove trailing zeros ...
[i]); } else { bi = RSAUtils.biFromString(blocks[i], key.radix); } block = key.barrett.powMod(bi, key.d); for (j = 0; j <= RSAUtils.biHighIndex(block); ++j) { result += String.fromCharCode(block.digits[j] & 255, block.digits[j] >> 8); } } // Remove trailing ...
I guess if greater than 1, I can cast it to an integer, use strlen to get the number of digits, subtract that from the number of formatted decimals, remove trailing zeros, and then remove a trailing period (if applicable). Just seems, however, that there should be a more straightforwar...
Trailing zeros: e.g., 2.22507385850720110e-308. Leading zeros in the exponent: e.g., 2.2250738585072011e-0308. (Combinations of the above) You can also alter the full 324 decimal place version of the number with leading and trailing zeros. ...
the regex removes any leading and trailing symbols and leading zeros. It doesnt validate the number, so 12 41 is considered to be correct input! english notation: /^.*?[0]*([\d\s]+)(([\.][\d]{0,2})([\d]*))?.*?$/