</label> <label> <span>联系邮箱 :</span> <input id="email" type="text" name="email" placeholder="联系邮箱" class="form-control input-lg" /> </label> <label> <span> </span> <input type="submit" class="button" value="Send" /> </label> </form>2.创建smtp.php文件1...
}$sent=TRUE;foreach($TOas$rcpt_to) {$rcpt_to=$this->get_address($rcpt_to);if(!$this->smtp_sockopen($rcpt_to)) {$this->log_write("Error: Cannot send email to ".$rcpt_to."\n");$sent=FALSE;continue; }if($this->smtp_send($this->host_name,$mail_from,$rcpt_to,$header,$...
1、下载phpmail压缩包,并解压。 2、创建index.html文件。并写入代码。 <form action="" method="post"> <p>收件人邮箱:<input type="text" name="toemail" id="mail"/></p> <p>标题:<input type="text" name="title" id="sub"/></p> <p>内容:<textarea name="content" cols="50" id="...
一、使用表单提交数据: 1. 前端部分,通过HTML中的form标签和input标签创建表单,并使用submit按钮提交表单。 2. 后端部分,通过$_POST数组接收前端提交的数据。 二、使用AJAX异步请求: 1. 前端部分,使用XMLHttpRequest对象或者jQuery中的$.ajax方法向后端发送异步请求。 2. 后端部分,通过$_POST或$_GET数组接收前端传...
To process the form, you need to check that it has been submitted, and then build the content of the email message. 1. Above the doctype in acknowledge.php, create a PHP code block like this: The name of the submit button in my form is send, so this confirms that $_POST['send']...
$sent = mail($emailadd, $subject, $text, 'From: '.$emailadd.'');if ($sent) { header("location: $url"); exit;} else { echo "There was an error sending the email. Please try again later <link back to form>";} It is kind of hard to tell about the rest of the code since...
<form action="zuizhong.php" method="post"> <input type="text" name="inquiry_lam_name_footer" placeholder='Your Name'> <input type="text" name="inquiry_lam_email_footer" placeholder='Your E-mail'> <input type="text" name="inquiry_lam_phone_footer" placeholder='Your Phone'> ...
在上述示例中,$("form").submit()函数用于捕获表单提交事件。然后,使用serialize()函数将表单数据序列化为字符串,并通过AJAX发送到send_email.php文件。最后,将服务器返回的结果显示在页面上的某个元素中(例如<div id="result"></div>)。 总结: 通过以上步骤,我们可以实现提交HTML表单并通过电子邮件发送...
您可以从表单中生成$message。就像$message = $_POST['FORM_FIELD_NAME'];
xhr.send(formData);} // 使用jQuery发送表单数据$(“#myForm”).submit(function(event) { event.preventDefault(); $.ajax({ url: “submit.php”, type: “POST”, data: $(this).serialize(), success: function(response) { // 表单提交成功后的处理 console.log(response); } });});“` 3....