However, despite these challenges, the tool demonstrated exceptional performance, above that of random guessing. Another challenge we encountered was the diversity and extensive length across conversations in ou
or neighbor. Similarly, the unknown caller could be a scammer trying to get your money. It is essential to know who called me from this phone number to act wisely. The article under review introducesFastPeopleSearch, its practical workability, and a wide range of additional tools to know who...
Something interesting noted is if I use any other stream cipher (let’s say Salsa) to encrypt a phone number and the opposition knows it is a phone number (7 numerical figures), the resulting ciphertext (same length as the plaintext) would still be pretty short and with the advantage of...
Further analysis also shows that not all our behavioral factors are useful for predicting gender. Table4shows, for instance, the most predictive features of gender in EU and SA and Figure7the accuracy of the algorithm as a function of the number of features used (forward feature selection). I...
Dijkstra's Algorithm Heaps Repeated K times Roman Conversion In Python Tree approximate_string_matching binary_search binomial_coefficient call-by-reference call-by-value crasher css dining_philosophers factorial fibonacci gitRanker graph guessing game heapsorter hello-world html integer_partition js-char-...
Table 4 shows, for instance, the most predictive features of gender in EU and SA and Figure 7 the accuracy of the algorithm as a function of the number of features used (forward feature selection). In both EU and SA, few features (≈25) are enough to reach a high accuracy. ...
The team analyzed the attributes of MasterPrints culled from real fingerprint images, and then built an algorithm for creating synthetic partial MasterPrints. Experiments showed that synthetic partial prints have an even wider matching potential, making them more likely to fool biometric security systems...
We are yet to discover an efficient algorithm that can find the factors of a number easily. What if I ask you: Could p possibly be 7? You can easily verify the answer right? Just divide 119 by 7! Multiplication is easy. Finding the original factors of a number is hard. So Q1 ...