1. The relationship between pH and pKa is expressed by the formula: pH = pKa + log([A-]/[HA]).2. This equation indicates that a lower pKa value signifies a more acidic substance.3. Conversely, a higher pKa value indicates a weaker acidity in the substance.4. Consequently,...
pH取决于溶液的浓度，这意味着弱酸实际上可以比稀强酸有更低的pH值；pKa则不受浓度影响，只与贡献或接...
It's worth noting that sometimes this equation is written for the Kavalue rather than pKa, so you should know the relationship: pKa = -logKa Assumptions for the Henderson-Hasselbalch Equation The reason the Henderson-Hasselbalch equation is an approximation is because it takes water chemistry out...
首先 例题里的酸 都是一元弱酸 当弱酸与其共轭碱共存时，电离平衡受同离子效应的影响 溶液中[H3O+]的浓度由弱酸与其共轭碱的浓度比决定 这里没有牵涉到平衡移动的问题 因为这个是标准的缓冲溶液 里面没有加入其他任何的酸或者碱 来调节PH 故不存在平衡移动的问题 况且弱酸的电离都很小 自身的电离...
Much computational research aimed at understanding ionizable group interactions in proteins has focused on numerical solutions of the Poisson–Boltzmann (PB) equation, incorporating protein exclusion zones for solvent and counterions in a continuum model. Poor agreement with measured pKas and pH-dependen...
a) Ka = -log pKa = 10^-3.75 = 1.78x10⁻⁴ = (1x10⁻¹⁴)/(1.78x10⁻⁴) = 5.61x10⁻¹¹ √(0.1 x 5.61x10⁻¹¹) = 2.37x10⁻⁶ pOH = -log(2.37x10⁻⁶) = 5.6 pH = 14 – pOH = 8.4 ...
pKa and pH - The fundamental distinction between pKa and pH is that pKa denotes an acid's dissociation, whereas pH denotes a system's acidity or alkalinity.
I think that this is a buffer, but I don't know what to do with the 1mmol NH4? So, I didn't take note of this concentration and I calculated the pH with the equation of Henderson-Hasselbach : pH = pKa + log (Base)/(Acid) ...
The isosbestic point occurs at a wavelength of 494 nm, with an absorbance of 0.46.doi:10.4236/ajac.2014.517135L. E. Vidal SalgadoC. Vargas-HernándezScientific Research美国分析化学(英文)L.E.V. Salgado and C.V.Hernandez, Spectrophotometric determination of the pKa, isosbestic point and equation ...
16.3: Henderson-Hasselbalch Equation The ionization-constant expression for a solution of a weak acid can be written as:Rearranging to solve for [H3O+] yields:Taking the negative logarithm of both sides of this equation giveswhich can be written aswhere pKa is the negative of the logarithm of...