(CASEWHENprovince_type='省内'THEN0ELSE1END) snFROMtable009where1=1ORDERBYCASEWHENid='全省'andtype='省内'THEN0ELSE1END,sn;--case...when..then...else... enddeletefromtable009whereid='11';--删除数据
SELECT id, type, county_code FROM tablename ORDER BY CASE type WHEN 2 THEN 1 ELSE 2 END, county_code; 在这个例子中,CASE语句根据type字段的值返回不同的排序权重(1或2)。然后,ORDER BY子句根据这些权重和county_code字段的值对结果进行排序。 验证排序结果是否符合预期: 执行上述SQL语句后,检查返回...
case...when...then...else...endcasecasewhen...then...else...endcase 1.1、IF-THEN IF条件表达式THEN主体部分ENDIF IF-THEN是IF结构最简单的形式,如果条件为true,则执行主体部分的脚本,否则不执行。例如: IFid=1THENupdatet_ordersetorder_code='123'whereid=1;ENDIF; 1.2、IF-THEN-ELSE IF条件表达式...
3.select top n * from (select top m * from table_name order by column_name ) a order by column_name desc --查询第N到M条记录。常用的分页也是这种方式。 1. 2. 3. CASE…END判断语句 CASE WHEN THEN END结构有两种书写方式 结构: 第一种格式简单的CASE 函数 CASE WHEN 条件1 THEN 结果1 WH...
order by seq_no --- SIZES_VALUE = (SELECT ARRAY_TO_STRING(ARRAY(SELECT ALT_LABEL||CASE WHEN COALESCE(LABEL,'') = '' THEN '' ELSE '('||LABEL||')' END FROM CNT_MEASUREMENT_TEMPLATE_SIZE WHERE PARENT_ID = MEASUREMENT_TEMPLATE.ID ORDER BY SEQ_NO),', ')); --- set sizes value...
这里通过into子句赋值给变量,返回的是结果的第一行或者null(查询返回零行),除非使用order by进行排序,否则第一行是不明确的,第一行之后所有的结果都会被丢弃。 如果加了strict选项,那么查询结果必须是恰好一行,否则就会报错。 举个例子,现在在a表中插入数据,表a数据如下。 然后从表中查询出name值赋值val。 CREATE...
explain(costs off)select c_custkey,count(o_orderkey)from customer left outer join orders on c_custkey=o_custkey and o_comment not like'%special%deposits%'group by c_custkey;QUERYPLAN---Finalize GroupAggregate Group Key:customer.c_custkey->Gather Merge Workers Planned:4->Partial GroupAggreg...
•语法:SELECT expression AS alias_name, aggregate_function(expression) FROM table_name GROUP BY expression; •示例:假设想要按照订单金额是否大于1000进行分组,并统计每个组的订单总金额,可以使用以下查询语句: SELECTCASEWHENorder_amount>1000THEN'大于1000'ELSE'小于等于1000'ENDAS订单金额区间,SUM(order_amou...
그러나 ELSE가 없으면 CASE_NOT_FOUND 예외가 발생합니다. 다음은 그 한 예입니다. CASE x WHEN 1, 2 THEN msg := 'one or two'; ELSE msg := 'other value than one or two'; END CASE; 검색 CASE CASE WHEN boolean-expression THEN ...
group by a.sys_project_id, a.project_code, a.area_id, a.type, a.category_value union all --合计 select max(e.short_name) as project_name, a.project_code, max(case when coalesce(d.parentid,''')=''' then d.name else concat(ppa.name,''/'', d.name) end) as area_name, a...