pgsql中在函数中使用returning 返回插入的值 DECLARE newId bigint;insert into tablea(id,A,B,C)values(id,a,b,c)returnid into newId; returning 返回多个值的情况 DECLARE newId bigint;a varchar;insert into tablea(id,A,B,C)values(id,a,b,c)returnid,A into newId,a;...
with--1.保存im发送信息msgInsertas(insertintomsgvalues('1',1,'{}')),--2 从用户接收id表中的id进行自增1reumIdInsertas(insertintoreumIdvalues(2,1)onconflict (uid) doupdatesetrid=reumId.rid+1returning rid),--3 用户接收表入库reumInsertas(insertintoreumvalues((selectridfromreumIdInsert limit...
insert into test(aa,bb) values('vb','ad'); insert into test(aa,bb) values('er','fg'); with "te" as (update test set aa = 'test',bb='test' where id =4 returning *) insert into test(aa,bb) select 'test','test' where (select count(*) from te) = 0...
量或标量变量列表。这通过书写基础 SQL 命令并增加一个 INTO 子句来达成 SELECT select_expressions INTO [STRICT] target FROM ...; INSERT ... RETURNING expressions INTO [STRICT] target; UPDATE ... RETURNING expressions INTO [STRICT] target; DELETE ... RETURNING expressions INTO [STRICT] target; 1...
(100), salary INTEGER ); -- 插入一些示例数据 INSERT INTO employees (name, salary) VALUES ('John', 5000), ('Jane', 6000), ('Bob', 7000), ('Alice', 8000); -- 使用UPDATE和WINDOW函数将所有员工的薪水增加10% UPDATE employees SET salary = salary + (salary * 0.1) RETURNING *; -- ...
PgSQL 自7.3起支持SRF( Set Returning Func. 集合返回函数) 配合有一些新的函数权限选项, 使schema 的设置更灵活性。SRF 除了手册里提到的内置函数 generate_series generate_subscript 外,自定义函数也可返回集合。 下面示例摘译自 PgSQL wiki :PL/PgSQL如何返回多行结果 ...
returning关键字:返回修改行,插入行,删除行的数据,‘returning *’意思是返回你操作的全部数据,也可以是你刚才修改,插入,删除数据的一部分,例如:returning id ,returning name…之类 UNION ALL 和UNION:union all ,解释为联合所有,union解释为联合,union或者union all实现把前后两个select集合的数据联合起来,组成一个...
'$p5k2$$7cxgxz4n$JSkgV8oGg72S1O6i2xYZSLEU2Yd6bdCO','0','admin','No','No','[email protected]','No',22,'11/5/2023 19:59:45','delete delete (admin)') RETURNING id INTO parent_user; INSERT INTO tmp_f6a8e872_b346_4184_889d_52ffeded463f (id) VALUES (parent_user); END...
with "别名" as (update 表名 set 字段名1= '更新的值',字段名2='更新的值' where 主键=需要更新的主键的值 returning *) insert into 表名(字段名1,字段名2) select '更新的值','更新的值' where (select count(*) from 别名) = 0 我自己写了个例子: create table test( id serial primary ke...
INSERT INTO your_table_name (name, age) VALUES (name, age) RETURNING id INTO new_id; RAISE NOTICE ‘Inserted ID: %’, new_id; 执行更新操作(假设要更新id为1的记录的年龄为30) UPDATE your_table_name SET age = 30 WHERE id = 1; ...