use strict; use warnings; use DateTime; use DateTime::TimeZone; # 解析日期 my $date_string = '2022-01-01T00:00:00'; my $date = DateTime->from_epoch(epoch => time); $date->set_time_zone('Asia/Shanghai'); # 转换时区 my $new_tz = 'America/New_York'; my $new_date = $date...
); $epoch_time = $dt->epoch; Find more detailed information on CPAN: Time::Local, DateTime. You can also use Date::Manip if you need more advanced date manipulation routines.Using the Date::Parse module (thanks to ericblue76):use...
复制 use Time::Local;$then=time() + 4*86400;$then=timegmlocaltime $then;# local epoch seconds$then-= $then % 86400;# truncate to the day$then=timelocalgmtime $then;# back to gmt epoch secondsprint scalar localtime $then, “\n”; 1. 2. 3. 4. 5. 6. 7. 8. 9. 【编辑推荐...
otherwise it is thelastweek of the previous year, and thenextweek is week1.%vis equivalent to ``%e-%b-%Y''.%Wis replaced by the week number of the year (Monday as the first day of the week) as a decimal number (00-53).%wis replaced by the weekday (Sunday as the first day o...
use Time::Local;$then= time()+4*86400;$then= timegm localtime$then; #localepoch seconds$then-=$then%86400; # truncate to the day$then= timelocal gmtime$then; # back to gmt epoch seconds print scalar localtime$then, “\n”;
您正在询问如何将日期字符串从UTC转换为另一个时区（Asia/Kolkata）。您的流程：string -> epoch -> ...
use DateTime; my $datetime = DateTime->new( day => 18, month => 7, year => 2003, hour => 12, minute => 00, second => 00, ); say $datetime; say $datetime->ymd; say $datetime->ymd('_'); say $datetime->hms; say $datetime->epoch; ...
perldatetimeparsingdatetime 54 如何将一个日期/时间数组(year, month, day, hour, minute, second)转换成epoch时间,即1970-01-01 00:00:00 GMT以来的秒数? 附加问题:如果给出日期/时间字符串,如何首先解析为(y,m,d,h,m,s)数组? - dreeves 2 这个问题的投票结果很奇怪。 - jdelator 2 必须注意:Uni...
DateTime模块 处理日期和时间。 my $dt = DateTime -> from_epoch(epoch => time); print $dt->ymd; 1. 2. ---第十二章 文件测试 - --- 文件测试操作符 -r -w -x -o :对目前的用户或组可读/写/执行/拥有的文件或目录 -R -W -X -O :对实际的...
/usr/bin/perl -w use strict; use DateTime; use DateTime::Format::Duration; # XXX: Create...