暴力解法,定义一个long类型的变量,for循环判断其平方是否小于num,但是不要写循环体,这样省时,最后直接判断其平方是否等于num。 public boolean isPerfectSquare(intnum) {if(num<=1) {returnnum==1; } long i =1;for( ; i*i <num; i++);returni*i ==num; } 03 第二种解法
public boolean isPerfectSquare(int num) { int lo = 1; int hi = 46340; while (lo <= hi) { int mid = lo + (hi - lo) / 2; if (mid * mid < num) { lo = mid + 1; } else if (mid * mid > num) { hi = mid - 1; } else if (mid * mid == num){ return true; ...
https://github.com/grandyang/leetcode/issues/367 类似题目: Sqrt(x) 参考资料: https://leetcode.com/problems/valid-perfect-square/ https://leetcode.com/problems/valid-perfect-square/discuss/83872/O(1)-time-c%2B%2B-solution-inspired-by-Q_rsqrt https://leetcode.com/problems/valid-perfect-squ...
Can you solve this real interview question? Valid Perfect Square - Given a positive integer num, return true if num is a perfect square or false otherwise. A perfect square is an integer that is the square of an integer. In other words, it is the produc
https://leetcode.com/problems/valid-perfect-square/ 题目: Given a positive integer num, write a function which returns True if num is a perfect square else False. Note: Do not use any built-in library function such as sqrt. Example 1: ...
valid perfect square(leetcode) valid perfect square 题目介绍 解题方法 最近在刷leetcode, 遇到一个很easy的问题,但是用蛮力的方法,根本解不开,想着应该是数学得某个知识,这个结介绍一下。 题目介绍 这个题目就是输入一个整数,来判断它是不是一个整数的平方,虽然可以用蛮力算法来解决,但是在提价的时候会遇到...
Leetcode: Perfect Squares,Givenapositiveintegern,findtheleastnumberofperfectsquarenumbers(forexample,1,4,9,16,...)whichsumton.Forexample,givenn=12,...
[leetcode-279-Perfect Squares]Given a positive integer n, find the least number of perfect square numbers (for example, 1, 4, 9, 16, ...) which sum to n. For example, given n = 12, return 3 because 12 = 4 + 4 + 4; given n = 13, return 2 because 13 = 4 + 9. Credits...
classSolution {public:boolisPerfectSquare(intnum) {longx =num;while(x * x >num) { x= (x + num / x) /2; }returnx * x ==num; } }; 本文转自博客园Grandyang的博客,原文链接:检验完全平方数[LeetCode] Valid Perfect Square,如需转载请自行联系原博主。
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