To make your job easier, we have given you a helper method named largestSquare() that takes a positive integer n and returns the largest perfect square less than or equal to n.我的代码在这……import java.util.*class ArrayBag public static int terms[]={0,0,0,0}...
解法一: 1publicclassSolution {2publicbooleanisPerfectSquare(intnum) {3if(num < 0)returnfalse;4if(num == 1)returntrue;5for(inti = 1; i<= num/i;i++){6if(i*i == num)returntrue;7}8returnfalse;9}10} 解法2: 二分查找法 (java 没有ac 仅供参考) 1publicclassSolution {2publicboolean...
public class Solution { public boolean isPerfectSquare(int num) { for(int i = 1; num > 0; i += 2){ num -= i; } return num == 0; } } 1. 2. 3. 4. 5. 6. 7. 8. python版本: class Solution(object): def isPerfectSquare(self, num): """ :type num: int :rtype: bool...
02 第一种解法 暴力解法,定义一个long类型的变量,for循环判断其平方是否小于num,但是不要写循环体,这样省时,最后直接判断其平方是否等于num。 public boolean isPerfectSquare(intnum) {if(num<=1) {returnnum==1; } long i =1;for( ; i*i <num; i++);returni*i ==num; } 03 第二种解法 使用...
Problem Given a positive integer num, write a function which returns True if num is a perfect square else False. Example For example: Given num = 16 ReturnsTrue Solution class Solution { public boolean isPerfectSquare(int num) { if (num == 1) return true; ...
Program to check if given number is perfect square in Kotlin packagecom.includehelpimport java.util.*//import kotlin.math.floor//import kotlin.math.sqrt//function to check perfect Square numberfuncheckPerfectSquare(number:Double):Boolean{//Square Root of Numbervalsq= Math.sqrt(number)//Floor va...
if (goodMask << x >= 0) return false; final int numberOfTrailingZeros = Long.numberOfTrailingZeros(x); // Each square ends with an even number of zeros. if ((numberOfTrailingZeros & 1) != 0) return false; x >>= numberOfTrailingZeros; // Now x is either 0 or odd. // In ...
starting from 1, until it becomes 0 or negative. If the value reaches 0 at some point, we can say that the number is a perfect square. However, if the value becomes negative without reaching 0, the number cannot be a perfect square. This is demonstrated below in C++, Java, and Python...
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Sally invited 17 guests to a dance party at her estate in the Hamptons. She assigned each guest a number from 2 to 18, keeping 1 for herself. At one point in the evening when everyone was dancing, Sally noticed the sum of each couple's numbers was a perfect square. Everyone was ...