for j in range(1, i + 1): square: int = j * j if square > i: break dp[i] = min(dp[i], dp[i - square] + 1) return dp 代码(Go) func numSquares(n int) int { // dp[i] 表示 i 最少能表示成 dp[i] 个完全平方数之和。 // 初始化为 n + 1 ,
代码如下: 1classSolution(object):2defisPerfectSquare(self, num):3"""4:type num: int5:rtype: bool6"""7left, right =0, num8whileleft <=right:9mid = (left+right) / 210ifmid ** 2 ==num:11returnTrue12elifmid ** 2 <num:13left = mid + 114else:15right = mid -116returnFalse...
Python3代码 classSolution:defnumSquares(self, n:int) ->int:# solution two: Lagrange's Four-square Theoremwhilen %4==0:# reduce nn /=4ifn %8==7:return4a =0whilea **2<= n: b =int((n - a **2) **0.5)ifa **2+ b **2== n:return(notnota) + (notnotb)# whether a an...
valid perfect square(leetcode) valid perfect square 题目介绍 解题方法 最近在刷leetcode, 遇到一个很easy的问题,但是用蛮力的方法,根本解不开,想着应该是数学得某个知识,这个结介绍一下。 题目介绍 这个题目就是输入一个整数,来判断它是不是一个整数的平方,虽然可以用蛮力算法来解决,但是在提价的时候会遇到...
publicclassSolution{/** * @param n: a positive integer * @return: An integer */publicintnumSquares(intn) {// write your code hereint[] f = newint[n +1];for(inti =0; i <= n; i++) { f[i] = i;// max square number is i itself with all 1for(intj =1; j * j <= ...
[LeetCode]Perfect Squares 作者是 在线疯狂 发布于 2015年9月9日 在LeetCode. 题目描述: Given a positive integer n, find the least number of perfect square numbers (for example, 1, 4, 9, 16, ...) which sum to n. For example, given n = 12, return 3 because 12 = 4 + 4 + 4; ...
GivenNaxis-aligned rectangles whereN>0,determineifthey all together form an exact coverofa rectangular region.Each rectangle is representedasa bottom-left point and a top-right point.For example,a unit square is representedas[1,1,2,2].(coordinateofbottom-left pointis(1,1)and top-right point...
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25 is a valid perfect square True 23 is a valid perfect square False Conclusion In this post, we saw one of the coding questions that are usually asked in interviews. Let us know how you would approach this problem in the comment section below. Happy coding!
Leetcode 367. Valid Perfect Square classSolution(object):defisPerfectSquare(self, num):""":type num: int :rtype: bool"""forxinrange(1000000):ifx*x==num:returnTruereturnFalse