完全数(Perfect number),又称完美数或完备数,是一些特殊的自然数。它所有的真因子(即除了自身以外的约数)的和(即因子函数),恰好等于它本身。请你完善下面Python程序,找出1000以内的所有完全数。 def perfect(m): if m<=1:return False sum=1 for i in range(): if : sum+=i return m==sum list1...
python if sum_of_divisors == num: result = "是完数" else: result = "不是完数" 输出判断结果: python print(f"{num} {result}") 将以上步骤整合成一个完整的Python程序如下: python def is_perfect_number(num): divisors = [i for i in range(1, num) if num % i == 0] sum_of_...
下面是整个问题的完整代码: defis_perfect_number(num):ifsum_of_factors(num)==num:returnTrueelse:returnFalsedefsum_of_factors(num):sum=0foriinrange(1,num):ifnum%i==0:sum+=ireturnsumfornuminrange(1,1001):ifis_perfect_number(num):print(num) 1. 2. 3. 4. 5. 6. 7. 8. 9. 10. ...
Here is source code of the Python Program to check if a number is a Perfect number. The program output is also shown below. n=int(input("Enter any number: "))sum1=0foriinrange(1,n):if(n % i==0): sum1=sum1 + iif(sum1==n):print("The number is a Perfect number!")else:...
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找出1000 以内所有的完全数,完全数 ( Perfect number ) 是一些特殊的自然数,它所有的真因子 ( 即除了自身以外的因子 ) 的和 ( 即因子 函数 ) 恰好等于它本身 [ 输入形式 ] 无 [ 输出形式 ] 6 28 496 相关知识点: 试题来源: 解析 Python代码如下: def find_perfect_numbers(): for n in range...
public static boolean isPerfectNumber(int num) { int originalNum = num; int lastNum = num; int index = 2; int newSum = 1; while (index < lastNum) { if(num % index == 0) { lastNum = num / index; newSum += index; newSum += lastNum; } index++; } return newSum == ori...
完全数(Perfect number),又称完美数或完备数,是一些特殊的自然数。它所有的真因子(即除了自身以外的约数)的和(即因子函数),恰好等于它本身。请你完善下面Python程序,找出1000以内的所有完全数。def perfect(m):if m<=1:return Falsesum=1 for i in range():___ if : ___ sum+=ireturn m==sumlist1=...
Python: 1 2 3 4 5 6 7 8 9 10 11 classSolution(object): defcheckPerfectNumber(self, num): """ :type num: int :rtype: bool """ ifnum <=0:returnFalse ans, SQRT=0,int(num**0.5) ans=sum(i+num//iforiinrange(1, SQRT+1)ifnotnum%i) ...
python3 赞同 0 添加评论 九章算法助教团队精选 更新于 6/9/2020, 7:04:17 PM java 我们只需要找到小于sqrt(n)sqrt(n)的约数就能把数n的所有约数求取出来了。 publicclassSolution{/***@param num:aninteger*@return: returns true when it isaperfect number and false when it is not*/public boolean...