To understand the output power of different audio devices such as speakers and amplifiers, two main parameters are Peak watts and RMS. They define the power in different ways and their difference are important for finding the output power of audio device
3. 扬声器功率指标类型 3.a. 平均功率.由于它来自RMS电压读数,所以经常被错误地称为”RMS”功率。RMS(均方根)仅在有负值和正值的变量 才有意义。因为功率只是正向的(从功率放大器至扬声器,而不是反过来),所以在RMS进程中不需要“开根号 ”和“平方”(只需要从数字中提取信号),只需要计算“平均值”。使...
average power=(p1*T1+p2*T2)/(T1+T2); average RMS power=sqrt((p1^2*T1+p2^2*T2)/(T1+T2)) 可以看出,average RMS power正如文章所说,没有什么物理意义。相对于peak RMS power,它更适合用于判定语音信号强弱程度。
单单说说你的3G G60C，这台功放的输出功率是125w x 2。380w是它的耗电功率。就现在而言，你的音箱额定功率是150w8Ω，而功放输出只有125w8Ω。功放输出远远小于音箱正常使用所需的驱动功率。所以，你的音箱和功放不匹配。如果是相同的4只音箱，有三种方法可以实现。第一，选择一台多通道功放。单台...
The ratio of the peak power and the average power of the output signal are used to determine if the power amplifier is operating in the linear region. If the ratio is too high, then the power amplifier may be operating in the linear region. By adjusting the power level of the input ...
The harvested power reaches about 312.4mW under random ground motions with root-mean-square (RMS) acceleration equal to 0.05g. Meanwhile, the comparison ... WA Shen,S Zhu,YL Xu - 《Sensors & Actuators A Physical》 被引量: 39发表: 2012年 Comparative analysis of methods for estimating arm ...
A figure of less than 1 mV RMS should be easy to obtain. HF noise is filtered by the reservoir and output capacitors and there are no significant internal noise sources, provided that the regulator isn’t allowed to oscillate, so that apart from supply-frequency ripple linear power supplies ...
Convert Power to a Peak Voltage, when to multiply by sqrt(2) I have a dBW value and dBW I understand to normally be given as representing a RMS Power (however this is not specificically ever stated and I am told its just assumed?) from dBW to Watts = 10^(dBW/10) This then giv...
额定功率:150瓦(RMS).最大功率:300瓦功率成分:LF8 " / HF1 "连接:四针双音响接口敏感度(瓦/秒):92dB最大的SPL:在1秒时的峰值104dB交叉频率:2千赫阻抗:8欧姆频率范围:80赫~20千赫颜色:灰色重量:12Kg尺寸(宽X深X高 299x269x435mm) 结果一 题目 英语翻译Rated power :150W (RMS)Program power :300W...
this is just the mean power of the signal and I think we should do the opertation of sqrt() to get the right meanSquareValue, Regards! Reply Krishna Sankarsays: February 10, 2012 at 6:00 am @Michael: If we put sqrt(), it becomes root mean square (rms) 😉 ...