from pathlib import Path # 字符串模式 path_str = "/path/to/file.txt" path = Path(path_str) # 获取路径的各个部分 print("文件名:", path.name) print("父目录:", path.parent) print("绝对路径:", path.absolute()) # 检查路径是否存在 print("路径是否存在:", path.exists()) # 检查路径...
Path.unlink(missing_ok=False):Remove this file or symbolic link. If the path points to a directory, use Path.rmdir() instead. If missing_ok is false (the default), FileNotFoundError is raised if the path does not exist. If missing_ok is true, FileNotFoundError exceptions will be igno...
frompathlibimportPath# 创建Path对象表示目录# 只是创建了路径对象,并没有真的在文件系统中创建这个目录parent_dir = Path(r"D:\py_related\test\new_directory")# 创建Path对象表示文件名file_name = Path("example.txt")# 使用除法操作连接目录和文件名full_path = parent_dir / file_name# 输出完整的路径...
Path.unlink(missing_ok=False):Remove this file or symbolic link. If the path points to a directory, use Path.rmdir() instead. If missing_ok is false (the default), FileNotFoundError is raised if the path does not exist. If missing_ok is true, FileNotFoundError exceptions will be igno...
pathlib的初衷之一就是用专门的对象来表示文件系统,instead of strings(而不是字符串)。确切地说,official documentation ofpathlib(pathlib的官方文档)称之为面向对象的文件系统路径(Object-oriented filesystem paths)。 当你把pathlib的语法和老的os.path的方式相比较时,object-oriented approach(面向对象的方式)是很...
file_path.rename(new_path) if __name__ == '__main__': target_directory = './test' # 需要批量重命名的路径 batch_rename(target_directory) 获取文件大小 import os from pathlib import Path print(os.path.getsize('test/1.mp4'))
Current directory: C:\Users\Jano\Documents\pyprogs\pathlib Home directory: C:\Users\Jano Python pathlib current file The__file__gives the path to the current running program. current.py #!/usr/bin/python from pathlib import Path p = Path(__file__) ...
extend(file_name) returnall_filespath=input('>>>请输入文件路径:') results=get_files(['.txt', '.jpg', '.py'], path) print(results) forfileinresults: print(file) Path.mkdir(mode=0o777, parents=False, exist_ok=False) Create a new directory at this given path. If mode is given,...
This time, I'm using a different approach to benchmarking because there is no one standard way to usepathlib. Sure, we can use it to create a path to a file, but we can also use it to print the current directory, list files with names matching a given pattern, or even quickly writ...
'Path is a directory.') elif path.is_file(): print('Path is a file.') else: ...