2:returnhasPathSum(root,0,sum); 3:}4:boolhasPathSum(TreeNode*root,intsum,inttarget){5:if(root==NULL)returnfalse;6:sum+=root->val;7:if(root->left==NULL&&root->right==NULL)//leaf8:{9:if(sum==target)10:returntrue;11:else12:returnfalse;13:}14:returnhasPathSum(root->left,sum,...
View Code SOLUTION 2: 使用DFS + Memory也可以解决问题。当前到终点有2种方式,往右,往下,两种路线,取一个较小的路线就行了。 View Code GITHUB: https://github.com/yuzhangcmu/LeetCode_algorithm/blob/master/dp/MinPathSum_1222_2014.java
题目地址:https://leetcode.com/problems/path-sum/#/description 题目描述 Given a binary tree and a sum, determine if the tree has a root-to-leaf path such that adding up all the values along the path equals the given sum. ...
[LeetCode]Path Sum Question Given a binary tree and a sum, determine if the tree has a root-to-leaf path such that adding up all the values along the path equals the given sum. For example: Given the below binary tree and sum = 22,...
returnresult+[path+[root.val]] else: returnself._pathSum(root.left,sum-root.val,path+[root.val],result)+self._pathSum(root.right,sum-root.val,path+[root.val],result) Leetcode 笔记系列的Python代码共享在https://github.com/wizcabbit/leetcode.solution...
public class Solution private int _sum; private int _count; public int PathSum(TreeNode root, int sum) _count = 0; _sum = sum; Travel(root, new List<int>()); return _count; private void Travel(TreeNode current, List<int> ret) ...
1. Description Path Sum III 2. Solution Recursive /** * Definition for a binary tree node. * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {}
Solution: 首先我们从根节点出发,去遍历这个根节点下所有满足条件的路径数目,每次到达一个节点,将传入的参数sum减去root的val,这是一个递归。然后我们需要遍历所有的根节点,那么又需要一个递归去遍历。两层递归。 /** * Definition for a binary tree node. ...
其中key表示从arr最左边开始累加和的过程中出现过的sum值,对应的value值则表示sum值最早出现的位置。根据这个思路,解这个类似问题就不难了。 根据上面类似问题的思路,我们来思考我们这道题目的解法,首先我们也需要用哈希表来存储在路径中出现过的sum值,不过value值的含义变了(因为不是求最长路径),value变成表示这个...
Left, remainSum) { return true } // 当右子结点存在,且存在一条右子结点到叶子路径上所有值到和为 remainSum ,则满足题意 if root.Right != nil && hasPathSum(root.Right, remainSum) { return true } // 左右子结点都不满足题意,返回 false return false } 题目链接: Path Sum: leetcode.com...