2:returnhasPathSum(root,0,sum); 3:}4:boolhasPathSum(TreeNode*root,intsum,inttarget){5:if(root==NULL)returnfalse;6:sum+=root->val;7:if(root->left==NULL&&root->right==NULL)//leaf8:{9:if(sum==target)10:returntrue;11:else12:returnfalse;13:}14:returnhasPathSum(root->left,sum,...
View Code SOLUTION 2: 使用DFS + Memory也可以解决问题。当前到终点有2种方式,往右,往下,两种路线,取一个较小的路线就行了。 View Code GITHUB: https://github.com/yuzhangcmu/LeetCode_algorithm/blob/master/dp/MinPathSum_1222_2014.java
113.Path Sum II Loading...leetcode.com/problems/path-sum-ii/ 1、 先读题,题目是求从根到叶子node,路径上所有数字之和等于sum 的所有路径。 2、先求出从root 到叶子node,所有路径的二维数组,再判断二维数组中那些元素之和等于sum值。 3、用递归深度优先搜索解决,用一个二维数组统计所有路径,一个一...
递归左右节点时,这时候的sum值应该是原sum值减去当前节点的值。 class Solution: def hasPathSum(self, root, sum): """ :type root: TreeNode :type sum: int :rtype: bool """ if root is None: return False if (root.val == sum) and (root.left is None) and (root.right is None): re...
题目地址:https://leetcode.com/problems/path-sum/#/description 题目描述 Given a binary tree and a sum, determine if the tree has a root-to-leaf path such that adding up all the values along the path equals the given sum. ...
returnresult+[path+[root.val]] else: returnself._pathSum(root.left,sum-root.val,path+[root.val],result)+self._pathSum(root.right,sum-root.val,path+[root.val],result) Leetcode 笔记系列的Python代码共享在https://github.com/wizcabbit/leetcode.solution...
题目地址:https://leetcode.com/problems/minimum-path-sum/description/ 题目描述 Given a m x n grid filled with non-negative numbers, find a path from top left to bottom right which minimizes the sum of all numbers along its path. ...
public class Solution private int _sum; private int _count; public int PathSum(TreeNode root, int sum) _count = 0; _sum = sum; Travel(root, new List<int>()); return _count; private void Travel(TreeNode current, List<int> ret) ...
931. 下降路径最小和 - 给你一个 n x n 的 方形 整数数组 matrix ,请你找出并返回通过 matrix 的下降路径 的 最小和 。 下降路径 可以从第一行中的任何元素开始,并从每一行中选择一个元素。在下一行选择的元素和当前行所选元素最多相隔一列(即位于正下方或者沿对角线向
1. Description Path Sum III 2. Solution Recursive /** * Definition for a binary tree node. * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {}