def print_pascal_triangle(num_rows): # 初始化杨辉三角形的第一行 triangle = [[1]] for i in range(1, num_rows): # 初始化当前行的第一个元素 prev_row = triangle[i - 1] curr_row = [1] # 根据上一行计算当前行的元素 for j in range(1, i): curr_row.append(prev_row[j - 1] ...
实现代码: ## LeetCode 118classSolution:defgenerate(self,num_rows):## The number of rowstriangle=[]forrow_numinrange(num_rows):## For a specific rowrow=[Nonefor_inrange(row_num+1)]## All None for this rowrow[0]=1## The most left number = 1row[-1]=1## The most right number...
代码(Python3) class Solution: def candy(self, ratings: List[int]) -> int: n: int = len(ratings) #将 ratings 收集成 (rating, index) 的列表, # 然后按照 rating 升序排序,方便后续状态转移 cells: List[Tuple[int, int]] = [(rating, i)for i, rating in enumerate(ratings)] cells.sort(...
3、在Python中难点应该就是每行的第一个元素和最后一个元素,最后一个元素通过判断j==i就可以区分了; 1classSolution:2#@return a list of lists of integers3defgenerate(self, numRows):4ret =[]5foriinrange(numRows):6ret.append([1])7forjinrange(1,i+1):8ifj==i:9ret[i].append(1)10else...
GivennumRows, generate the firstnumRowsof Pascal's triangle. For example, givennumRows= 5, Return [ [1], [1,1], [1,2,1], [1,3,3,1], [1,4,6,4,1] ] 代码:oj测试通过 Runtime: 46 ms 1classSolution:2#@return a list of lists of integers3defgenerate(self, numRows):4ifnum...
Pascal’s Triangle 题目大意 输出帕斯卡三角前N行 1 121 1331 解题思路 注意帕斯卡三角中,除了首尾,其他值为上一层的两个邻值的和 代码 class Solution(object): def generate(self, numRows): """ :type numRows: int :rtype: List[List[int]] ...
3、在Python中难点应该就是每行的第一个元素和最后一个元素,最后一个元素通过判断j==i就可以区分了; 1classSolution:2#@return a list of lists of integers3defgenerate(self, numRows):4ret =[]5foriinrange(numRows):6ret.append([1])7forjinrange(1,i+1):8ifj==i:9ret[i].append(1)10else...
[LeetCode]Pascal's Triangle Given numRows, generate the first numRows of Pascal's triangle. For example, given numRows = 5, Return 思考:边界单独考虑。 ...Pascal's Triangle @LeetCode ...LeetCode——Pascal's Triangle Given numRows, generate the first numRows of Pascal's triangle. For...
Another interesting pattern in Pascal's Triangle is that the sum of the numbers in each row gives the powers of 2. If we sum the numbers in the first few rows, you get:Row 0: 1 = 20 Row 1: 1 + 1 = 21 Row 2: 1 + 2 + 1 = 22 Row 3: 1 + 3 + 3 + 1 = 23 ...
Given an index k, return the kth row of the Pascal's triangle.For example, given k = 3, Return [1,3,3,1].题目大意给定一个整数k,返回帕斯卡三角形的第k行(序号从0开始)解题思路和上一题类似代码class Solution(object): def getRow(self, rowIndex): """ :type rowIndex: int :rtype: ...