import java.util.function.Predicate; public class Main { public static void main(String[] args) { // Define the palindrome check lambda expression Predicate < String > isPalindrome = str -> { String reversed = new StringBuilder(str).reverse().toString(); return str.equals(reversed); }; /...
直接搬代码 #include<bits/stdc++.h> using namespace std; #define uint unsigned long long int read(){ int x=0,f=1;char ch=getchar(); while(!isdigit(ch)){if(ch=='-') f=-1;ch=getchar();} while(isdigit(ch)){x=(x<<3)+(x<<1)+ch-48;ch=getchar();} return x*f; } co...
If you are thinking of converting the integer to string, note the restriction of using extra space. You could also try reversing an integer. However, if you have solved the problem "Reverse Integer", you know that the reversed integer might overflow. How would you handle such case? There i...
利用栈,将slow走的节点的值存起来,当slow走到链表中点后,每走一步就将节点的值和栈的值比较。注意判断链表节点个数为奇数或偶数时,处理稍有差别。 boolisPalindrome(ListNode*head) { ListNode* fast =head; ListNode* slow =head; stack<int>s;while(fast && fast->next) { s.push(slow->val); fast=...
#include<iostream> #include<cstdio> #include<cstring> using namespace std; const int MAXN=40; typedef long long LL; int tmp[MAXN],num[MAXN]; int dp[MAXN][MAXN][MAXN][2]; //dp[i][j][k][r]:k进制下从i位到j为,状态为r(1表示回文)时回文数的个数 int dfs(int st,int cur,...
234. Palindrome Linked List recursion not work, stack will be overflow using iterative way...LeetCode 234 Palindrome Linked List LeetCode 234 Palindrome Linked List Problem Description: 判断链表是否是回文链表。所谓回文,即序列从两头起以相同速度向中间靠拢的过程中,对应位置的元素相同,比如1-2-2-1或...
If you are thinking of converting the integer to string, note the restriction of using extra space. You could also try reversing an integer. However, if you have solved the problem "Reverse Integer", you know that the reversed integer might overflow. How would you handle such case?
Palindrome Time Limit: 4000/2000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 3281 Accepted Submission(s): 1136 Problem Description A palindrome is a symmetrical string, that is, a string read identically from left to right as well as from right to left...
#include<bits/stdc++.h> using namespace std; int main() { string s,tmp; cin>>s; for(int t=0;t<10;t++) { tmp=s; reverse(s.begin(),s.end()); if(s==tmp) { printf("%s is a palindromic number.",s.c_str()); return 0; } printf("%s + %s = ",tmp.c_str(),s.c...
(int i=e; i>=s; --i) using namespace std; typedef long long ll; typedef pair<int,int> pii; const int maxn = 1e6 + 5; string s; int n; int seed,mod,hs1[maxn],hs2[maxn],bas[maxn]; // hs看情况开 void init(int* hs){ s=' '+s; bas[0]=1; rep(i,1,n+1){ ...