思路1:遍历一次链表,用一个数组存储链表节点值,然后用双指针法判断数组是否是回文的。需要额外O(n)的空间。 C++ classSolution{public:boolisPalindrome(ListNode* head){if(!head || !head->next)returntrue; vector<int> vec;while(head) { vec.push_back(head->val); head = head->next; }for(inti ...
先看看list有多长。然后把前半截的node values逐个push到一个stack里。然后从后半截开始逐个比较node value和stack[-1]。注意list长度为奇偶的两种情况。奇数时,先pop掉中间一个。 1classSolution(object):2defisPalindrome(self, head):3"""4:type head: ListNode5:rtype: bool6"""7ifnotheadornothead.next...
⭐ Leetcode 解題紀錄 ⭐題型資料結構Python SolutionC++ SolutionNote ⭐BFS 相關題型 ⭐ 104 Maximum Depth of Binary Tree BFS (分層) Python 94 Binary Tree Inorder Traversal BFS (分層) Tree Python 內含 處理 Tree 樹問題的重點 102 Binary Tree Level Order Traversal BFS (分層) Tree Python ...
Can you solve this real interview question? Palindrome Linked List - Given the head of a singly linked list, return true if it is a palindrome or false otherwise. Example 1: [https://assets.leetcode.com/uploads/2021/03/03/pal1linked-list.jpg] Inpu
LeetCode 234. 回文链表 Palindrome Linked List Table of Contents 一、中文版 二、英文版 三、My answer 四、解题报告 一、中文版 请判断一个链表是否为回文链表。 示例1: 输入: 1->2 输出: false 示例2: 输入: 1->2->2->1 输出: true
Leetcode 234 Palindrome Linked List 复杂度为时间O(n) 和空间(1)解法,1.问题描写叙述给定一个单链表,推断其内容是不是回文类型。比如1–>2–>3–>2–>1。时间和空间复杂都尽量低。2.方法与思路1)比較朴素的算法。因为给定的数据结构是单链表,要訪问链表的尾部元素,
Leetcode之Palindrome Linked List 问题 问题描述: Given a singly linked list, determine if it is a palindrome. Follow up: Could you do it in O(n) time and O(1) space? 示例: 1->2->9->4->9->2->1 return true; 1->2-&... ...
LeetCode: 234. Palindrome Linked List 题目描述 Given a singly linked list, determine if it is a palindrome. Example 1: Input: 1->2 Output: false 1. 2. Example 2: Input: 1->2->2->1 Output: true 1. 2. Follow up: Could you do it in O(n) time and ...
Leetcode-Easy 234. Palindrome Linked List 描述: 判断一个单链表是否左右对称 代码语言: 代码运行次数: # Definitionforsingly-linked list.#classListNode:# def__init__(self,x):# self.val=x # self.next=NoneclassSolution(object):defisPalindrome(self,head):""":type head:ListNode:rtype:bool"""...
LeetCode problem solving notes. Determine whether a linked list is a palindrome linked list. First convert the linked list into an array, and then judge whether the array is a palindrome array.