} Python: importstringdefis_palindrome(text: str) ->bool:'是否为回文'#1、先去除标点符号以及空格,并将所有字母小写化result =''foriinrange(len(text)):ifnottext[i]instring.punctuation +'': result+=text[i].lower()print(result)#2、判断是否为回文n =len(result)foriinrange(len(result) // ...
oxyribo: no, stack <- oed, word <- xyribo xyribo: no, stack <- xoed, word <- yribo yribo: no, stack <- yxoed, word <- ribo ribo: no, stack <- ryxoed, word <- ibo ibo: no, stack <- iryxoed, word <- bo bo: no, stack <- biryxoed, word <- o o: yes, need...
But note that those letters must all appear in one word/phrase, because there is no "a", and we only get word boundaries at "a"s. And of course, there is no single word that contains those letters. In general, take a word (such as "an asparagus" or "a biologist"), split it ...