思路1:遍历一次链表,用一个数组存储链表节点值,然后用双指针法判断数组是否是回文的。需要额外O(n)的空间。 C++ classSolution{public:boolisPalindrome(ListNode* head){if(!head || !head->next)returntrue; vector<int> vec;while(head) { vec.push_back(head->val); head = head->next; }for(inti ...
先看看list有多长。然后把前半截的node values逐个push到一个stack里。然后从后半截开始逐个比较node value和stack[-1]。注意list长度为奇偶的两种情况。奇数时,先pop掉中间一个。 1classSolution(object):2defisPalindrome(self, head):3"""4:type head: ListNode5:rtype: bool6"""7ifnotheadornothead.next...
Can you solve this real interview question? Palindrome Linked List - Given the head of a singly linked list, return true if it is a palindrome or false otherwise. Example 1: [https://assets.leetcode.com/uploads/2021/03/03/pal1linked-list.jpg] Inpu
LeetCode: 234. Palindrome Linked List 题目描述 Given a singly linked list, determine if it is a palindrome. Example 1: Input: 1->2 Output: false 1. 2. Example 2: Input: 1->2->2->1 Output: true 1. 2. Follow up: Could you do it in O(n) time and ...
【LeetCode】234 Palindrome Linked List Total Accepted: 1116 Total Submissions: 4295 My Submissions Question Solution Given a singly linked list, determine if it is a palindrome. Follow up: Could you do it in O(n) time and O(1) space?
My code: importjava.util.Stack;/** * Definition for singly-linked list. * public class ListNode { * int val; * ListNode next; * ListNode(int x) { val = x; } * } */publicclassSolution{publicbooleanisPalindrome(ListNode head){if(head==null||head.next==null)returntrue;ListNode slow=...
234. Palindrome Linked List 请判断一个链表是否为回文链表。 示例1: 输入:1->2输出:false 示例2: 输入:1->2->2->1输出:true 进阶: 你能否用 O(n) 时间复杂度和 O(1) 空间复杂度解决此题? 来源:力扣(LeetCode) 链接:https://leetcode-cn.com/problems/palindrome-linked-list著作权归领扣网络所有...
LeetCode problem solving notes. Determine whether a linked list is a palindrome linked list. First convert the linked list into an array, and then judge whether the array is a palindrome array.
Leetcode-Easy 234. Palindrome Linked List 描述: 判断一个单链表是否左右对称 代码语言: 代码运行次数: # Definitionforsingly-linked list.#classListNode:# def__init__(self,x):# self.val=x # self.next=NoneclassSolution(object):defisPalindrome(self,head):""":type head:ListNode:rtype:bool"""...
LeetCode 234. 回文链表 Palindrome Linked List Table of Contents 一、中文版 二、英文版 三、My answer 四、解题报告 一、中文版 请判断一个链表是否为回文链表。 示例1: 输入: 1->2 输出: false 示例2: 输入: 1->2->2->1 输出: true