import java.util.*; public class Example1 { public static void main(String[] args) { // creating an instance of Scanner class Scanner sc=new Scanner(System.in); System.out.println("Enter a number to check palindrome: "); // to take input from user int num = sc.nextInt(); // co...
importjava.util.Scanner;publicclassPalindrome{publicstaticvoidmain(String[] args){Scannersc=newScanner(System.in);longn;while((n = sc.nextLong()) !=0){// 输入以零结束longnum;booleanbook=true;Stringstr=null;for(inti=2;i <=16;i++) {// (2-16) 进制num = decimalToMRadix(n, i);// ...
}char[] data2 =newchar[data.length];intlen=stack.size();for(inti=0; i < len; i++) { data2[i] = stack.pop(); }Stringreversed=newString(data2);returnoriginal.equals(reversed); } } The example uses the JavaStackcontainer to build a reversed string. 该示例使用Java Stack容器构建反向...
Below image shows the output of the above longest palindrome java program. We can improve the above code by moving the palindrome and longest lengths check into a different function. However, I have left that part for you. :) Please let me know if there are any other better implementations ...
publicbooleanisPalindrome(String text){Stringclean=text.replaceAll("\\s+","").toLowerCase();intlength=clean.length();intforward=0;intbackward=length -1;while(backward > forward) {charforwardChar=clean.charAt(forward++);charbackwardChar=clean.charAt(backward--);if(forwardChar != backwardChar)...
public boolean isPalindrome(int x) { if(x<0) { return false; } if(x==0) { return true; } StringBuilder in = new StringBuilder(); int a = x; while(a!=0) { in.append(a%10); a/=10; } String o = String.valueOf(x); ...
); } // length of the string // if there is one character string - returing true int len = str.length(); if (len <= 1) { return true; } // Converting the string into uppercase // to make the comparisons case insensitive String strU = str.toUpperCase(); // result variable /...
int i = 0, j = s.length() - 1; while(i < j) { if(s.charAt(i) != s.charAt(j)) return false; i++; j--; } return true; } } 这个博客还用了一种set的方法: http://www.cnblogs.com/grandy... 暂时还没看懂,明天再看下。。
int end = s.length() - 1; OUT: while(start < end) { while(!Character.isLetter(s.charAt(start)) && !Character.isDigit(s.charAt(start))) { start++; if (start > end) // check valibility for every index, if start=end only 1 char left, return true, stay in loop break OUT; ...
res.add(list); } } } } return res; } public boolean isPalindrome(String s){ int left = 0, right = s.length() - 1; while(left < right){ if(s.charAt(left++) != s.charAt(right--)) return false; } return true; } }