Below image shows the output of the above longest palindrome java program. We can improve the above code by moving the palindrome and longest lengths check into a different function. However, I have left that part for you. :) Please let me know if there are any other better implementations ...
}publicbooleanisPalindromeUsingStringBuffer(String text){Stringclean=text.replaceAll("\\s+","").toLowerCase();StringBufferplain=newStringBuffer(clean);StringBufferreverse=plain.reverse();return(reverse.toString()).equals(clean); }Copy In the code snippet, we invoke thereverse()method from theStr...
A palindrome is a word, phrase, number, or other sequence of characters which reads the same backward as forward, such as madam. Write a java program to find the longest palindrome present in a given string. For example, in the string a
Here, we are implementing a java program that will read a string and check the palindrome words in string also find the occurrences of words in a given string. Submitted by Chandra Shekhar, on January 08, 2018 Given a string and we have to find occurrences of palindrome words using java ...
Java: importjava.util.Scanner;publicclassPalindrome{publicstaticvoidmain(String[] args){Scannersc=newScanner(System.in);longn;while((n = sc.nextLong()) !=0){// 输入以零结束longnum;booleanbook=true;Stringstr=null;for(inti=2;i <=16;i++) {// (2-16) 进制num = decimalToMRadix(n, i...
import java.util.function.Predicate; public class Main { public static void main(String[] args) { // Define the palindrome check lambda expression Predicate < String > isPalindrome = str -> { String reversed = new StringBuilder(str).reverse().toString(); return str.equals(reversed); }; /...
importjava.util.Scanner;publicclassPalindrome {privatestaticintlen;//全局变量整型数据privatestaticcharp[];//全局变量数组publicstaticvoidmain(String args[]) {Scanner sc=newScanner(System.in); String str; str=sc.nextLine(); len=str.length();//令len的值为数组长度p=str.toCharArray();//将字符串...
import java.util.*; public class Example1 { public static void main(String[] args) { // creating an instance of Scanner class Scanner sc=new Scanner(System.in); System.out.println("Enter a number to check palindrome: "); // to take input from user int num = sc.nextInt(); // co...
代码细节就是有一个isPalindrome的helper function。 一个hashmap存入所有<string, idx> paris加速查询。 容易出bug的两个地方, 以["abcd", "dcba", "lls", "s", "sssll"]为例。 1. 如果一个str本身就是panlindrome,reverse就是本身,一定在hashmap里,去重的方法就是判断map.get(reverse(str)) != i...
两个词形成的string一样不算重复,只有当两个词的组合重复时才算重复。例如: ["", "aa"],结果应该是[(0,1), (1,0)]。那么什么时候可能出现重复呢?["ab", "ba"],这种两个单词形成了palindrome,如果在ab和ba的两边都查一遍肯定会重复。可以看出规律是当map里面有其中一个词的reverse时,就少算一边即可...