Palindrome Linked List Given a singly linked list, determine if it is a palindrome. Follow up: Could you do it in O(n) time and O(1) space? 反转链表 复杂度 时间O(N) 空间 O(1) 思路 两个指针都从头出发,快指针每次两步,慢指针每次一步,这样快指针的下一个或下下个为空时,慢指针就在链...
Given a singly linked list, determine if it is a palindrome. Follow up: Could you do it in O(n) time and O(1) space? 解题思路: 使用O(n)的时间复杂度及O(1)的时间复杂度表明顺序遍历链表以及不能够开辟跟链表相当的空间,这样可以找出中间的位置,然后将后半部分的链表反转,然后跟前半部分的链表...
More:【目录】LeetCode Java实现 回到顶部 Description https://leetcode.com/problems/palindrome-linked-list/ Given a singly linked list, determine if it is a palindrome. Example 1: Input: 1->2 Output: false Example 2: Input: 1->2->2->1 Output: true Follow up: Could you do it in O(...
Given a singly linked list, determine if it is a palindrome. Follow up: Could you do it in O(n) time and O(1) space? 解题思路: 使用O(n)的时间复杂度及O(1)的时间复杂度表明顺序遍历链表以及不能够开辟跟链表相当的空间,这样可以找出中间的位置,然后将后半部分的链表反转,然后跟前半部分的链表...
234. Palindrome Linked List Given a singly linked list, determine if it is a palindrome. Follow up: Could you do it in O(n) time and O(1) space? /** * Definition for singly-linked list. * public class ListNode { * int val;...
Could you do it in O(n) time and O(1) space? Hide Tags Linked List Two Pointers 【解题思路】 1、遍历链表,快慢指针,找到链表后半部分。 2、反转链表,能够參考Reverse Linked List 3、然后比較前半部分和后半部分的val值。 Java AC /** ...
// this change would reflect in the parent recursive calls left = left->next; // In order for linked list to be palindrome, the character at the left // node should match with the character at the right node return (prevLeft->data == right->data); ...
bitset tree linked-list stack queue graph graph-algorithms string strings matrix array sum bits string-manipulation arrays palindrome permutation linkedlist trees ctci Updated Jun 13, 2021 Java Smile-SA / palindrome.js Star 23 Code Issues Pull requests 3D visual probe for 3D monitoring and Dig...
234. Palindrome Linked List Given a singly linked list, determine if it is a palindrome. Follow up: Could you do it in O(n) time and O(1) space? ** 解题思路 ** (1)用快慢指针找到中点 (2)然后把右边那一半反转。 (3)再依次比较左右两边,如果不相等,则返回false; 若左右两边对称相等,则...
Given a singly linked list, determine if it is a palindrome. Example 1: Input: 1->2 Output: false Example 2: Input: 1->2->2->1 Output: true Follow up: Could you do it in O(n) time and O(1) space? 解法1: 利用stack的FILO原理。