We will also take the help of while loop and if-else conditional block. import java.util.*; public class Example1 { public static void main(String[] args) { // creating an instance of Scanner class Scanner sc=new Scanner(System.in); System.out.println("Enter a number to check ...
在while循环中,我们开始比较字符串两侧的字符;从最左边和最右边的字符开始, 一直走到字符串的中间 Java Palindrome with Stack TheStackis a last-in-first-out (LIFO) collection. packagecom.zetcode.palindrome;importjava.util.Stack;publicclassPalindrome4{publicstaticvoidmain(String[] args){ System.out.printl...
publicbooleanisPalindrome(String text){Stringclean=text.replaceAll("\\s+","").toLowerCase();intlength=clean.length();intforward=0;intbackward=length -1;while(backward > forward) {charforwardChar=clean.charAt(forward++);charbackwardChar=clean.charAt(backward--);if(forwardChar != backwardChar)r...
Problem Solution: In this program, we will read an integer number and check number is palindrome or not and print the appropriate message on the console screen. Program/Source Code: The source code tofind the given number is palindrome or not using theforloopis given below. The given program...
Using string buffer , import java.util.*; import java.lang.*; class Seventeen { public static void main(String args[]) { Scanner sc=new Scanner(System.in); String str=sc.next(); String reverse = new StringBuffer(str).reverse().toString(); ...
Given an integer number and we have to check whether it is palindrome or not using java program.Check palindrome number in javaimport java.util.Scanner; class CheckNumberPalindromeOrNotPalindromeClass{ public static void main(String[] args){ //rev variable is used to store reverse of actual_...
By chance we a classic algorithm: KMPforcomputing the longest "prefix/suffix"in a string. The algorithm is ver very elegant!!!Reference: https://leetcode.com/discuss/52564/a-kmp-based-java-solution-with-explanationhttp://blog.csdn.net/v_july_v/article/details/7041827http://www.rudy-yuan....
fromcollectionsimportdeque# Input: Take a string from the userword=input()# Function to check string using a deque and while loopdefis_palindrome(s):chars=deque(s)whilelen(chars)>1:ifchars.popleft()!=chars.pop():returnFalsereturnTrue# Check and print the resultifis_palindrome(word):print...
If there is no break statement after the loop has finished, the number is a palindrome. Python code to check if a number is a palindrome using iteration: def is_palindrome(num): str_num = str(num) start = 0 end = len(str_num) - 1 while start < end: if str_num[start] != str...
value); temp = number; while(number>0) { rem = number%10; number = parseInt(number/10); final = final*10+rem; } if(final==temp) { window.alert("The inputed number is Palindrome"); } else { window.alert("The inputted number is not palindrome"); } } Calling JavaScript...