Below image shows the output of the above longest palindrome java program. We can improve the above code by moving the palindrome and longest lengths check into a different function. However, I have left that part for you. :) Please let me know if there are any other better implementations or i...
A string that is equal to its reverse string is known as palindrome string. To implement the program for checking whether a given string is a palindrome or not, we have created a function "isPalindrome()".In the function, We are checking for whether a string is an empty string or not ...
publicbooleanisPalindrome(String text){Stringclean=text.replaceAll("\\s+","").toLowerCase();intlength=clean.length();intforward=0;intbackward=length -1;while(backward > forward) {charforwardChar=clean.charAt(forward++);charbackwardChar=clean.charAt(backward--);if(forwardChar != backwardChar)r...
For more Practice: Solve these Related Problems: Write a Java program to implement a lambda expression that checks if a string is a palindrome by reversing it and comparing. Write a Java program to create a lambda that checks palindromicity of a string ignoring case and non-alphanumeric charac...
Java: importjava.util.Scanner;publicclassPalindrome{publicstaticvoidmain(String[] args){Scannersc=newScanner(System.in);longn;while((n = sc.nextLong()) !=0){// 输入以零结束longnum;booleanbook=true;Stringstr=null;for(inti=2;i <=16;i++) {// (2-16) 进制num = decimalToMRadix(n, i...
A palindrome is a word, phrase, number, or other sequence of characters which reads the same backward as forward, such as madam. Write a java program to find the longest palindrome present in a given string. For example, in the string a
for(int j = 0; j <= words[i].length(); j++){ String str1 = words[i].substring(0, j); String str2 = words[i].substring(j); if(isPalindrome(str1)){ String str2rvs = new StringBuilder(str2).reverse().toString(); if(map.containsKey(str2rvs) && map.get(str2rvs) != i)...
function palindromeFn(string) { const stringLength = string.length; for (let i = 0; i < stringLength / 2; i++) { if (string[i] !== string[stringLength - 1 - i]) { return 'It is not a palindrome.'; } } return 'It is a palindrome.'; } console.log(palindromeFn('aviddiva...
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#include<string.h> #define max(a,b) a>b?a:b char a[5010],b[5010]; int p[2][5010]; int main(){ int i,j,n; while(scanf("%d",&n)!=EOF) { scanf("%s",a); for(i=n-1,j=0;i>=0;i--) b[j++]=a[i]; memset(p,0,sizeof(p)); ...