Palindrome Degree I'm trying to solve this problem:http://www.codeforces.com/problemset/problem/7/D And here is my solution:http://www.codeforces.com/contest/7/submission/2865747 My code might look little bit u
7D Palindrome Degree By alphadr, 12 years ago, http://codeforces.com/problemset/problem/7/D Can someone please explain to me the problem ? I don't understand how the result was 6 for the second input case.+1 alphadr 12 years ago 9 ...
are(k - 1)-palindromes. By definition, any string (even empty) is 0-palindrome. Let's call the palindrome degree of stringssuch a maximum numberk, for whichsisk-palindrome. For example, "abaaba" has degree equals to3. You are given a string. Your task is to find the sum of t...
Palindrome Degree(CodeForces 7D)—— hash求回文 学了kmp之后又学了hash来搞字符串。这东西很巧妙,且听娓娓道来。 这题的题意是:一个字符串如果是回文的,那么k值加1,如果前一半的串也是回文,k值再加1,以此类推,算出其k值。打个比方abaaba,k值为3,abaxxaba,k值为1。现在,给出一个串,让你求这个串的所...
题目链接:http://codeforces.com/contest/7/problem/D D. Palindrome Degree time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Stringsof lengthnis calledk-palindrome, if it is a palindrome itself, and its prefix and suffix of length ...
Palindrome Degree hash D. Palindrome Degree题目连接:http://www.codeforces.com/contest/7/problem/DDescriptionString s of length n is called k-palindrome, if it is a palindrome itself, and its prefix and suffix of length are (k - 1)-palindromes. By definition, any string (even empty)...
Codeforces Beta Round #7--D. Palindrome Degree(Manacer),求出每一个点为中心的最长字符串,推断该串是不是从开头的回文串。 #include<cstdio>#include<cstring>#include<algorithm>usingnamespacestd;intp[12000000],dp[6000000];chars[1200000
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Codeforces Beta Round #7 D. Palindrome Degree hash 题目连接: http://www.codeforces.com/contest/7/problem/D Description String s of length n is called k-palindrome, if it is a palindrome itself, and its prefix and suffix of length are (k - 1)-palindromes. By definition, any string...
#include<queue> #include<string> #include<stdlib.h> #include<algorithm> using namespace std; #define N 5001000 #define mod 1000000007 #define hehe 137731735 #define ll __int64 ll n; char s[N]; ll x[N], y[N]; ll dp[N];