LeetCode算法题-K-diff Pairs in an Array(Java实现) 这是悦乐书的第254次更新,第267篇原创 01 看题和准备 今天介绍的是LeetCode算法题中Easy级别的第121题(顺位题号是532)。给定一个整数数组和一个整数k,您需要找到数组中唯一的k-diff对的数量。 这里k-diff对被定义为整数对(i,j),其中i和j都是数组中...
链接:https://leetcode-cn.com/problems/k-diff-pairs-in-an-array/description/ Q: 给定一个整数数组和一个整数k, 你需要在数组里找到不同的k-diff数对。这里将k-diff数对定义为一个整数对 (i, j), 其中 i 和 j 都是数组中的数字,且两数之差的绝对值是k. 示例 1: 思路:k小于0 返回0 ...
链接:https://leetcode-cn.com/problems/k-diff-pairs-in-an-array/description/ Q: 给定一个整数数组和一个整数 k, 你需要在数组里找到不同的 k-diff 数对。这里将 k-diff 数对定义为一个整数对 (i, j), 其中 i 和j 都是数组中的数字,且两数之差的绝对值是 k. 示例 1: 思路:k小于0 返回0 ...
原题链接:https://leetcode.com/problems/k-diff-pairs-in-an-array/description/ 这道题目很有意思哦,但是我始终没有写出实现来,下面是抄袭讨论区的答案啦: importjava.util.HashMap;importjava.util.Map;/** * Created by clearbug on 2018/2/26. */publicclassSolution{publicstaticvoidmain(String[] arg...
import java.util.Arrays; import java.util.Scanner; public class sample { public static void main(String args[]){ //Reading the array from the user Scanner sc = new Scanner(System.in); System.out.println("Enter the size of the array that is to be created: "); int size ...
Given an array of integers and an integer k, you need to find the number of unique k-diff pairs in the array. Here a k-diff pair is defined as an integer pair (i, j), where i and j are both numbers in the array and their absolute difference is k. ...
for key, value in pairs(表) do -- 循环体 end 1. 2. 3. 示例4:遍历数组型表 local myArray = {12, 13, 55, 88, 60} for k, v in pairs(myArray) do print("Index:", k, "Value:", v) end 1. 2. 3. 4. 示例5:遍历键值对型表 ...
629. K Inverse Pairs Array 技术标签: leetcode-javaGiven two integers n and k, find how many different arrays consist of numbers from 1 to n such that there are exactly k inverse pairs. We define an inverse pair as following: For ith and jth element in the array, if i < j and a[...
Java Code: // Define the Main class.publicclassMain{// Define a method to check if there is a pair of elements in the array// that sum up to 'x'.staticbooleansum_pair(intarr_int[],intn,intx){intk;// Find the pivot point where the array is rotated.for(k=0;k<n-1;k++)if...
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