1classSolution {2publicintminPairSum(int[] nums) {3Arrays.sort(nums);4intmax =Integer.MIN_VALUE;5intres =Integer.MAX_VALUE;6intleft = 0;7intright = nums.length - 1;8while(left <right) {9inti =nums[left];10intj =nums[right];11max = Math.max(max, i +j);12left++;13right--;...
class Solution { public: int twoCitySchedCost(vector<vector<int>>& costs) { int cost_sum = 0; //最后的费用总和 multimap<int,int> nums; //使用关键词(key)允许重复的multimap。记录A的索引和费用 multimap<int,int>::iterator iter; //定义multimap迭代器 int i = 0; while(i < costs.size...
Given an arrayAof positive integers,A[i]represents the value of thei-th sightseeing spot, and two sightseeing spotsiandjhave distancej - ibetween them. Thescoreof a pair (i < j) of sightseeing spots is (A[i] + A[j] + i - j): the sum of the values of the sightseeing spots,minu...
908-middle-of-the-linked-list 943-sum-of-subarray-minimums 966-binary-subarrays-with-sum 97-interleaving-string README.md stats.jsonBreadcrumbs Data-Structures-Leetcode /2473-max-sum-of-a-pair-with-equal-sum-of-digits / README.mdLatest...
【python-双指针】pair with target sum 找不到该题对应leetcode的哪一题。。。 问题描述: 给定一个有序数组和一个目标和,在数组中找到一对和等于给定目标的数组,有就返回下标,没有就返回[-1,-1]。 例如: s=[1,2,3,4,5,6,7,8],k=14,返回[5,7],也就是下标为5和下标为7的和为14:6+8=14...
【python-双指针】pair with target sum 找不到该题对应leetcode的哪一题。。。 问题描述: 给定一个有序数组和一个目标和,在数组中找到一对和等于给定目标的数组,有就返回下标,没有就返回[-1,-1]。 例如: s=[1,2,3,4,5,6,7,8],k=14,返回[5,7],也就是下标为5和下标为7的和为14:6+8=14...
本题是leetcode121这道题的翻版,做法完全一样,也是扫一遍数组,维护两个值,一个是a[i]+i的最大值,另一个是a[i]+a[j]+i-j的最大值. classSolution:defmaxScoreSightseeingPair(self, A: List[int]) ->int: best, ret=0, 0fori, vinenumerate(A): ...
leetcode 1021. Best Sightseeing Pair For each position, use A[i] to record the max value of A[j] + j, which j <= i. And iterate the array, in each round, we can compute the maximum value where i picked from the previous and j fixed to the current index....
LeetCode 646. Maximum Length of Pair Chain You are given n pairs of numbers. In every pair, the first number is always smaller than the second number. Now, we define a pair (c, d) can follow another pair (a, b) if and only if b < c. Chain of pairs can be formed in this ...
Explanation: i = 0, j = 2,A[i] + A[j] + i - j = 8 + 5 + 0 - 2 = 11 Note: 2 <= A.length <= 50000 1 <= A[i] <= 1000 解题思路:本题和【leetcode】123. Best Time to Buy and Sell Stock III有点类似。题目要求求出A[i] + A[j] + i - j最大值,这个表达式可以等...