Leetcode: Paint House II There are a row of n houses, each house can be painted with one of the k colors. The cost of painting each house with a certain color is different. You have to paint all the houses such that no two adjacent houses have the same color. The cost of painting...
There are a row ofnhouses, each house can be painted with one of thekcolors. The cost of painting each house with a certain color is different. You have to paint all the houses such that no two adjacent houses have the same color. The cost of painting each house with a certain color...
ans != MAX: ans 即为满足题意的所有染色方案中,花费最小的费用 DP 常见的三种优化方式见LeetCode 583 这题的思路。 本题可以采用滚动数组的方式进行优化,因为每一行的状态依赖上一行的所有状态,所以无法采用其他两种方式进行优化。 使用滚动数组的话,能将空间复杂度从O(m * target * n) 优化为 O(target *...
paint i 和 ii一样,只是限定了k=3,所以可以写的简单一些。 paint ii https://leetcode.com/problems/paint-house-ii/ 未压缩空间: classSolution{public:intminCostII(vector<vector<int>>&costs){intn=costs.size();if(n==0)return0;intm=costs[0].size();vector<vector<int>>dp(n,vector<int>(m...
265. Paint House II https://leetcode.com/problems/paint-house-ii/discuss/69492/AC-Java-solution-without-extra-space
可以2个柱子颜色相同,则起点从2开始, 之前的所有情况,包括0 和 1 都要分别列出来写 [思维问题]: 列了几步以后觉得列不完,没思路:从小到大,反正只有相同、不相同两种情况,分情况讨论就行了 [一句话思路]: 第三根柱子开始有讨论余地,从此开始进行分类讨论。
There are a row of n houses, each house can be painted with one of the k colors. The cost of painting each house with a certain color is different. Yo
house 0 is color 2, house 1 is color 3, house 2 is color 2, 2 + 5 + 3 = 10 LeetCode上的原题,请参见我之前的博客Paint House II。 classSolution {public:/** * @param costs n x k cost matrix * @return an integer, the minimum cost to paint all houses*/intminCostII(vector<ve...
Or paint house 0 into color 2, paint house 1 into color 0. Minimum cost: 3 + 2 = 5. Follow up: Could you solve it in O(nk) runtime? 答案 直接改编Paint House题的答案 O(nk^2) classSolution{publicintminCostII(int[][]costs){if(costs.length==0)return0;intn=costs.length,k=cost...
265. Paint House II There are a row ofnhouses, each house can be painted with one of thekcolors. The cost of painting each house with a certain color is different. You have to paint all the houses such that no two adjacent houses have the same color....