The oxidation state of sulphur is calculated as shown below. $ \Rightarrow 2( + 1) + 2(x) + 2( - 1) + 6( - 2) = 0$ $ \Rightarrow 2 + 2x - 2 - 12 = 0$ $ \Rightarrow 2 + 2x - 14 = 0$ $ \Rightarrow 2x - 12 = 0$ ...