具体sql如下: CREATEORREPLACEfunctionGetWeekNum(currentDateINdate,weekStandardINvarchar2)returnvarchar2asfirstDayWeekNo NUMBER;--本年1号周几(以日历为基础,周一为第一天)fisrtWeekDayCount NUMBER;--本年第一周天数(以weekNo为标准)dayCount NUMBER;--总天数weekCount NUMBER;--总周数beginif currentDateisnul...
1、使用TO_CHAR函数 TO_CHAR函数可以将日期转换为字符串,并指定格式,我们可以使用’D’作为格式代码,表示星期几,要计算2022年1月1日是星期几,可以使用以下SQL语句: SELECT TO_CHAR(TO_DATE('20220101', 'YYYYMMDD'), 'D') AS weekday FROM DUAL; 执行结果: weekday 5 从结果可以看出,2022年1月1日是星期...
createorreplacefunctionGet_weekday(pDatedate)returnnumberis vResult number; begin selectcaseto_char(pDate,'FmDay','nls_date_language=english') when'Monday'then 1 when'Tuesday'then 2 when'Wednesday'then 3 when'Thursday'then 4 when'Friday'then 5 when'Saturday'then 6 when'Sunday'then 7 endd...
SQL> select to_char(sysdate,'YYYY-MM-DD HH24:MI:SS') d1 from dual; 1. D1 --- 2010-05-13 22:56:38 TO_CHAR的其它用法示例 1 SQL> SELECT TO_CHAR(date '2010-02-12', 'D') week_dayth,--周第几天(1-7),星期天=1,星期一=2,星期二=3,星期三=4,星期四=5,星期五=6,星期六=...
去掉的是周六/7，周日/1两天周末 具体SQL如下、这是避免日期格式本地化的版本 select count(1) from ( select to_char(TO_DATE('2016-12-24','yyyy-MM-dd') - level, 'd') DOW from dualconnect by level <= trunc(TO_DATE('2016-12-24','yyyy-MM-dd') - TO_DATE('2016-11-...
JOB_TYPE=>'plsql_block', JOB_ACTION=>'insert into emp select * from scott.emp where empno=7396', REPEAT_INTERVAL=>'freq=yearly;byyearday=-2', ENABLED=>TRUE); END; / 1. 2. 3. 4. 5. 6. 7. 8. 从上图可以看出,job的执行时间为17年12月30日,即17年的倒数第二天。
具体sql如下：CREATE OR REPLACE function GetWeekNum(currentDate IN date,weekStandard IN varchar2) return varchar2 as firstDayWeekNo NUMBER; --本年1号周⼏（以⽇历为基础，周⼀为第⼀天）fisrtWeekDayCount NUMBER; --本年第⼀周天数(以weekNo为标准)dayCount NUMBER; --总天数 weekCount ...
SELECTTO_CHAR(currdate,'fmDay')INTOtheDayFROMdual; /*countitonlyifitisaweekday*/ IFtheDay<> 'Saturday' AND theDay<>'Sunday' THEN countBusiness := countBusiness + 1; END IF; END LOOP; RETURN (countBusiness); END; / SQL> SELECT num_Business_Days(to_date('2015-04-21','yyyy-mm-...
第一部分:oracle sql日期比较: oracle sql日期比较: 在今天之前: select * from up_date where update < to_date('2007-09-07 00:00:00','yyyy-mm-dd hh24:mi:ss') select * from up_date where update <= to_date('2007-09-07 00:00:00','yyyy-mm-dd hh24:mi:ss') ...
ORACLE SQL计算同一个月的一周中的天数 我想这就是你要找的问题: SELECT WEEK AS WEEK_NUMBER, COUNT(*) AS WEEK_DAYSFROM (SELECT TO_CHAR(FIRST_DAY + (LEVEL-1), 'IW') AS WEEK FROM (SELECT supplied_date AS FIRST_DAY, LAST_DAY(supplied_date) - SUPPLIED_DATE+1 AS DAYS FROM (SELECT TO...