Example: ROUND() function using negative decimal places SELECT ROUND(34.4158,-1) FROM dual; Here is the result. ROUND(34.4158,-1) ----------------- 30 The above statement will round the given number 34.4158 from the left of decimal place up to 1 place. Previous:REMAINDER Next:SIGN Follow us onFacebookandTwi...
How to round date functions in Oracle? The ROUND() function in Oracle is used to round a specified date to the nearest unit defined by a format model. It follows the rules of the Gregorian calendar, allowing users to manipulate dates effectively for various purposes. Uses of Oracle ROUND(da...
One of our developers showed me the following discrepancy with the ROUND() function. The only difference that I can see is when the input value to the round() function is derived from a math operation. I'd just like to know, is this a bug or if it is intended functionality? SQL> se...
One of our developers showed me the following discrepancy with the ROUND() function. The only difference that I can see is when the input value to the round() function is derived from a math operation. I'd just like to know, is this a bug or if it is intended functionality? SQL> se...
oracle中Function函数的使用 1.函数调用限制函数示例 SQL只能调用带有输入参数,不能带有输出,输入输出函数。 SQL不能使用PL/SQL的特有数据类型(boolean,table,record等)。 SQL语句中调用的函数不能包含INSERT,UPDATE和DELETE语句。 2.函数示例 --定义行类型
SELECT round(0.5) FROM dual; -- 结果为1 SELECT round(1.5) FROM dual; -- 结果为2 SELECT round(2.5) FROM dual; -- 结果为2,而非3 复制代码 如果需要更传统的四舍五入方式,可以使用TRUNC和CEIL函数组合实现: CREATE OR REPLACE FUNCTION custom_round(p_number NUMBER, p_precision NUMBER) RETURN...
select round(-123.456, 2) from dual; 回传 -123.46 下面参考:https://blog.csdn.net/spurs611/article/details/81481730 4.NVL()函数 NVL(a1,a2) 语法:如果a1为null,返回a2,否则返回a1。 NVL2(a1,a2,a3) 语法:如果a1不为null,返回a2;a1为null,返回a3。
首先你的例子数据错了，不是21号，应该是24号。这样就没问题了。看你列出的数据，应该是格式由小到大，逐步四舍五入的一个过程。这个算法如下：round(带小时分秒日期, 格式)格式是 秒SS，精确到秒。分MI，到分，秒数30是分界线，相当于四舍五入的5，如果秒超过30，向前进1 时HH，如果分...
CREATE OR REPLACE FUNCTION round(timestamp, text) RETURNS timestamp AS $m$ DECLARE r timestamp; BEGIN IF $2 = 'minute' THEN SELECT date_trunc($2, $1 + interval '30 second') INTO r; ELSIF $2 = 'hour' THEN SELECT date_trunc($2, $1 + interval '30 minute') INTO r; ELSIF $2...
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