hex2bn在openSSL中的神奇分段故障EN###1、下载openssl源码 https://www.openssl.org/source/ ###2...
OpenSSL是一种开放源码的SSL实现,用来实现网络通信的高强度加密,现在被广泛地用于各种网络应用程序中。 OpenSSL 1.0.2及更早版本、1.0.1及更早版本在函数BN_hex2bn/BN_dec2bn的实现上存在安全漏洞,可导致空指针间接引用及堆破坏等问题。 漏洞来源: Guido Vranken 解决方案: 临时解决方法: 如果不能及时安装补丁,...
b = BN_new(); gx = BN_new(); gy = BN_new(); z = BN_new();//初始化一个空算法组group = EC_GROUP_new(EC_GFp_mont_method());//将国密算法的参数转为大数BN_hex2bn(&p, _P); BN_hex2bn(&a, _a); BN_hex2bn(&b, _b); BN_hex2bn(&gx, _Gx); BN_hex2bn(&gy, _G...
pPubKey = EVP_PKEY_new(); bigE = BN_new(); bigN = BN_new(); BN_hex2bn(&bigE, cerPubE); BN_hex2bn(&bigN, cerPubN); RSA_set0_key(rsaPubCtx, bigN, bigE, NULL); EVP_PKEY_set1_RSA(pPubKey, rsaPubCtx); X509_set_pubkey(x509, pPubKey); asnInteger = ASN1_INTEGER_new(...
void BN_clear_free(BIGNUM *a); 相当与将BN_free和BN_clear综合,要不就赋值0,要不就释放空间。 2.上下文情景函数,存储计算中的中间过程 BN_CTX *BN_CTX_new(void);申请一个新的上下文结构 void BN_CTX_init(BN_CTX *c);将所有的项赋值为0,一般BN_CTX_init(&c) ...
serial = BN_bn2hex(bignum); if (serial == NULL) { ulRet = CERT_ERR_FAILED; goto FREE_MEMORY; } BN_free(bignum); if (!lptcSN) { *pulLen = strlen(serial) + 1; ulRet = CERT_ERR_OK; goto FREE_MEMORY; } if (*pulLen < strlen(serial) + 1) ...
(2)OpenSSL实现Menezes-Vanstone算法主要代码 //加密操作,对( ml,m2)在有限域zp内赋随意值如下 BN.hex2bn(&ml,”3A2794482D6410697 C85 FA4643BAI DAEA76 FFAE6EC26A2C8"); BN_hex2bn( &m2,"AF7DF34CDA2DF2ACC65 C31BE95 A3888FC5DCC7 04461308EC"); ...
CVE-2017-3739: BN_hex2bn/BN_dec2bn NULL pointer deref/heap corruption CVE-2017-3740: BN_mod_inverse with odd modulus produces incorrect results CVE-2017-3732: Potential timing side channel in DSA signature generation 请注意,这只是其中的一部分漏洞列表,不一定是全部的漏洞列表。如果您需要更详细的...
22、 y_coordinate, ctx) )goto clean_up;if ( !(x_coordinate_str = BN_bn2hex(x_coordinate) )goto clean_up;printf(x coordinate in SM2 public key (in hex form):n); printf(%snn, x_coordinate_str);if ( !(y_coordinate_str = BN_bn2hex(y_coordinate) )goto clean_up;printf(y coord...
In the BN_hex2bn function the number of hex digits is calculated using an int value |i|. Later |bn_expand| is called with a value of |i * 4|. For large values of |i| this can result in |bn_expand| not allocating any memory because |i * 4| is negative. This leaves ret->d...