{if(s[i] ==t[i])continue;returns.substr(i) == t.substr(i+1); }returntrue;//说明前面的都相等只有最后一个不匹配}boolisSameLen(strings,stringt) {intcnt =0;for(inti =0; i < s.size(); i++) {if(s[i] !=t[i]) cnt++; }returncnt ==1; }boolisOneEditDistance(strings,strin...
Given two strings S and T, determine if they are both one edit distance apart. 72. Edit Distance的类似题目,编辑距离是从一个单词变成另一个单词的变换步骤。变换步骤可以是:插入,删除和替换。所以考虑三种情况: 1. 长度之差大于1,直接返回False 2. 长度之差等于1,长的字符串可去掉一个字符,剩下的字...
Leetcode[161] One Edit Distance LeetCode[161] One Edit Distance Given two strings S and T, determine if they are both one edit distance apart. String 复杂度 O(N),O(1) 思路 考虑如果两个字符串的长度 > 1,是肯定return false; 当两个字符串中有不同的字符出现的时候,说明之后的字符串一定要...
Leetcode: One Edit Distance 1. 注意这道题:Must be exactly one distance apart. Not the same. 1publicclassSolution {2publicbooleanisOneEditDistance(String s, String t) {3for(inti=0; i<Math.min(s.length(), t.length()); i++) {4if(s.charAt(i) !=t.charAt(i)) {5if(s.length()...
161. One Edit Distance Given two strings S and T, determine if they are both one edit distance apart. 分析:https://segmentfault.com/a/1190000003906621 虽然我们可以用Edit Distance的解法,看distance是否为1,但Leetcode中会超时。这里我们可以利用只有一个不同的特点在O(N)时间内完成。如果两个字符串...
Provide all my solutions and explanations in Chinese for all the Leetcode coding problems. Same as this: LeetCode All in One 题目讲解汇总(持续更新中...) Note: All explanations are written in Github Issues, please do not create any new issue or pull request in this project since the proble...
One Edit Distance.md update Oct 17, 2019 Leetcode-162. Find Peak Element.md update Oct 9, 2019 Leetcode-164. Maximum Gap.md update Sep 19, 2019 Leetcode-165. Compare Version Numbers.md update Sep 15, 2019 Leetcode-168. Excel Sheet Column Title.md update Sep 17, 2019 Leetcode-169....
Given two strings S and T, determine if they are both one edit distance apart. 2、问题描述: 这道题是之前那道Edit Distance的拓展,然而这道题并没有那道题难,这道题只让我们判断两个字符串的编辑距离是否为1,那么我们只需分下列三种情况来考虑就行了: ...
Given two strings S and T, determine if they are both one edit distance apart. 思路: 两个字符串是否只通过一步变换(替换、删除、增加)就变成相同字符串。 如果字符串长度差大于1,肯定是不可能。 如果两个字符串本来就相同,也不可能。 可能的情况只存在于字符串长度相同但字符串不相同或长度差为1。
LeetCode072——编辑距离 我的LeetCode代码仓:https://github.com/617076674/LeetCode 原题链接:https://leetcode-cn.com/problems/edit-distance/description/ 题目描述: 知识点:动态规划 思路:动态规划 一看到题目的时候,我其实是懵的,感觉无从下手。但其实本题是一个经典的动态规划问题。 状态定义: f(x, ...